Answered: A baseball is thrown up with intial…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A baseball is thrown up with intial vertical of 15 m/s. How long will it take for the ball to return to the same spot where it originated?

Expert Solution

Step 1

A baseball is thrown upwards at a certain velocity. Now to calculate the total time taken by the ball to reach the same spot from where it was thrown we first calculate the time taken for the ball to reach the maximum height and then the time taken to fall and reach the spot from where it was thrown.

At the topmost height the velocity of the baseball is zero.

So employing kinematical equation

$v^{2} - u^{2} = - 2 g h$

where u is the initial velocity and acceleration due to gravity is taken to be negative as per convention and h is the maximum height reached.

$u^{2} = 2 g h$

$h = \frac{15^{2}}{2 \times 9.8}$

$h = 11.5 m$

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