A bar magnet enters a long solenoid which has an ammeter attached in series to both ends. Explain why a reading on the ammeter is briefly shown and then records zero current. A ABCD The magnetic flux linkage in the coil increases and then decreases. The magnetic flux linkage in the coil decreases and then increases. The magnetic flux linkage in the coil increases and is then constant. The magnetic flux linkage in the coil is always constant.
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- An air-core circular solenoid is shown in the figure below. A current of 13.0 A is established in thewire which makes up this solenoid. The solenoid has 222 turns a) What is the magnetic field at its center? b) What is its self-inductance? c) How much energy is stored in the solenoid?A rectangular coil with sides 0.120 m by 0.210 m has 495 turns of wire. It is rotated about its long axis in a uniform magnetic field of 0.590 T that is perpendicular to the long axis. At what frequency f, in complete cycles per second, must the coil be rotated for it to generate a maximum voltage of 115 V? f = Hz * TOOLS x10A rectangular conducting loop has sides a = 0.065 m, sides b = 0.15 m, and resistance R = 55 Ω. It moves into a magnetic field of magnitude B = 0.81 T with speed v = 5.5 m/s. Refer to the diagram. A) Find the current, Ii, in amperes, flowing in the loop as it enters the magnetic field. B) Find the current, If, in amperes, in the loop as it leaves the magnetic field. It leaves at the same speed it enters.
- A car generator turns at 400 rpm when the engine is idling. Its 300 turn, 5.1 cm by 8.15 cm rectangular coil rotates in an adjustable magnetic field so that it can produce sufficient voltage even at low rpms. What is the field strength (in T) needed to produce a 27 V peak emf?1. A conducting loop of arca A and resistance R lics at right angles to a spatially uniform magnetic field. At time t = 0, the magnetic field and loop current are both zero. Subsequently, the current increases according to I (t) = bt², where b is a constant with units A/s?. Find an expression for the magnetic field strength as a function of time.A dc generator is rated at 20 kW, 250 V, and 80 A when it rotates at 1500 rpm. The resistance of the armature windings is 0.34 2. Part A Calculate the "no-load" voltage at 1500 rpm (when there is no circuit hooked up to the generator). Express your answer using two significant figures. V ΑΣΦ Val = 0 ? kV Review | Constants
- R OF е Fapp Figure P20.18 2003 Thomson Brooks Cole (c20p18) Consider the arrangement shown in Figure P20.18. Assume that R = 7.00 £2 and I = 1.00 m, and that a uniform 1.60-T magnetic field is directed into the page. At what speed should the bar be moved to produce a current of 0.400-A in the resistor?Refer To: Ref 22-2 Which one of the following statements concerning this situation is true? Since the circuit moves with constant speed, the force F does zero work. The induced current flows clockwise around the circuit. As the circuit moves through the field, the field does work to produce the current. If the circuit were replaced with a wooden loop, there would be no induced emf. The temperature of the circuit remains constant.Please explain
- The 12.0 cm long rod as shown moves at 4.00 m/s.What is the strength of the magnetic field if a 95.0 V emf isinduced?Two coils with iron cores are positioned as shown in the figure. The smaller coil is part of a circuit with a battery and a switch. Immediately after the switch Sis closed, which one of the following statements is true? O A magnetic field that points away from the smaller coil appears inside the larger coil. O An induced current will flow from right to left in R. O A magnetic field that points away from the larger coil appears inside the smaller coil. O A current will pass through r, but there will be no current through R. O An induced current will flow from left to right in R.Please Help ASAP!!!