A bar ABC fixed at both ends A and C is loaded by an axial load (P) at C. If the distances AB and BC are equal to a and b respectively then find the reactions at the ends A and C. An axial force of 20 kN is applied to a steel bar ABC which is fixed at both ends A and C as shown in Fig. 4.8. A = 200 mm A = 100 mm 20 kN A B 2 m 1 m Fig. 4.8 Determine the reactions at both the supports and stresses developed in two parts of the bar. Take

A bar ABC fixed at both ends A and C is loaded by an axial load (P) at C. If the distances AB and BC are equal to a and b respectively then find the reactions at the ends A and C. An axial force of 20 kN is applied to a steel bar ABC which is fixed at both ends A and C as shown in Fig. 4.8. A = 200 mm A = 100 mm 20 kN A B 2 m 1 m Fig. 4.8 Determine the reactions at both the supports and stresses developed in two parts of the bar. Take

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

2. A bar ABC fixed at both ends A and C is loaded by an axial load (P) at C. If the distances AB and
BC are equal to a and b respectively then find the reactions at the ends A and C.
3. An axial force of 20 kN is applied to a steel bar ABC which is fixed at both ends A and C as
shown in Fig. 4.8.
2
A = 200 mm
2
A = 100 mm
20 kN+
A
В
C
2 m
1m -
Fig. 4.8
Determine the reactions at both the supports and stresses developed in two parts of the bar. Take
E = 200 GPa.
[Ans. R = R = 10 kN ; 0AB = 50 MPa (C); 0BC = 100 MPa (T)]
%3D
%3D

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