A ball, with a mass of 5 kg, acceelerates in the +a direction with a magnitude of 5 m/s? and in the -y direction with a magnitude of 2 m/s2. What is the acceleration vector that describes this motion? What is the net force on this ball?
A ball, with a mass of 5 kg, acceelerates in the +a direction with a magnitude of 5 m/s? and in the -y direction with a magnitude of 2 m/s2. What is the acceleration vector that describes this motion? What is the net force on this ball?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter3: Vectors
Section: Chapter Questions
Problem 13PQ: In Chapter 5, you will study a very important vector, force. Each case in Figure P3.13 shows an...
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Question
![**Problem Statement:**
A ball, with a mass of 5 kg, accelerates in the \(+x\) direction with a magnitude of 5 m/s\(^2\) and in the \(-y\) direction with a magnitude of 2 m/s\(^2\).
1. What is the acceleration vector that describes this motion?
2. What is the net force on this ball?
**Solution Explanation:**
To find the acceleration vector, we combine the accelerations in the \(x\) and \(y\) directions:
- The acceleration in the \(x\)-direction is \(+5 \, \text{m/s}^2\).
- The acceleration in the \(y\)-direction is \(-2 \, \text{m/s}^2\).
Thus, the acceleration vector \(\mathbf{a}\) is \(\mathbf{a} = (5 \, \text{m/s}^2) \, \mathbf{i} + (-2 \, \text{m/s}^2) \, \mathbf{j}\).
To find the net force, we use Newton's second law, \(\mathbf{F} = m \mathbf{a}\), where \(m = 5 \, \text{kg}\).
Substitute the given values:
\[
\mathbf{F} = 5 \, \text{kg} \cdot \left[(5 \, \text{m/s}^2) \, \mathbf{i} + (-2 \, \text{m/s}^2) \, \mathbf{j}\right]
\]
This results in:
\[
\mathbf{F} = (25 \, \text{N}) \, \mathbf{i} + (-10 \, \text{N}) \, \mathbf{j}
\]
Therefore, the net force on the ball is \(\mathbf{F} = 25 \, \text{N} \, \mathbf{i} - 10 \, \text{N} \, \mathbf{j}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff0caab8e-c04c-4583-a44d-8cce85aff4a0%2F0d4f5a0a-86c3-4dad-b64e-40a738e75d58%2F637bb6l_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A ball, with a mass of 5 kg, accelerates in the \(+x\) direction with a magnitude of 5 m/s\(^2\) and in the \(-y\) direction with a magnitude of 2 m/s\(^2\).
1. What is the acceleration vector that describes this motion?
2. What is the net force on this ball?
**Solution Explanation:**
To find the acceleration vector, we combine the accelerations in the \(x\) and \(y\) directions:
- The acceleration in the \(x\)-direction is \(+5 \, \text{m/s}^2\).
- The acceleration in the \(y\)-direction is \(-2 \, \text{m/s}^2\).
Thus, the acceleration vector \(\mathbf{a}\) is \(\mathbf{a} = (5 \, \text{m/s}^2) \, \mathbf{i} + (-2 \, \text{m/s}^2) \, \mathbf{j}\).
To find the net force, we use Newton's second law, \(\mathbf{F} = m \mathbf{a}\), where \(m = 5 \, \text{kg}\).
Substitute the given values:
\[
\mathbf{F} = 5 \, \text{kg} \cdot \left[(5 \, \text{m/s}^2) \, \mathbf{i} + (-2 \, \text{m/s}^2) \, \mathbf{j}\right]
\]
This results in:
\[
\mathbf{F} = (25 \, \text{N}) \, \mathbf{i} + (-10 \, \text{N}) \, \mathbf{j}
\]
Therefore, the net force on the ball is \(\mathbf{F} = 25 \, \text{N} \, \mathbf{i} - 10 \, \text{N} \, \mathbf{j}\).
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given Data :
The mass of the ball is given as Mb = 5 Kg.
The acceleration of the ball in the x-direction is given as
The acceleration of the ball in the y-direction is given as
The negative sign indicates that the ball is moving in the negative y-direction.
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