A ball roles off a table as shown in the figure below with a horizontal velocity vx= 5 m/s. If the height of the table y=1, how far will the ball have fallen after the first half of its time in the air? Hint: First calculate the time in the air and plug 1/2 of this value into the Δy formula. You can also set up a proportion.
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A ball roles off a table as shown in the figure below with a horizontal velocity vx= 5 m/s. If the height of the table y=1, how far will the ball have fallen after the first half of its time in the air? Hint: First calculate the time in the air and plug 1/2 of this value into the Δy formula. You can also set up a proportion.
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- A student fires a cannonball vertically upwards with a speed of 39.0m/s. Determine all unknowns and answer the following questions. Neglect drag and the initial height and horizontal motion of the cannonball. What was the cannonball's maximum height? unit How long did the cannonball rise? unit What was the cannonball's total flight time? unit check answers cannot be de Unit 12: forces and motion review, one-dimensional motion problems Desmos Scientific Online CalculatorThe last part of YOUR lab (Part 3) is NOT covered in the video. It is, however, exactly like second part of the "Bull's Eye" lab where you predicted where the ball would land. If, after you complete Parts 1 and 2 of this lab, you have this Data: Launch Height: y = 114 cm Horizontal Launch Velocity: v = 457 cm/s. How far, x, does the ball travel? Give your answer in cm to 3 significant figures (no decimal places)Based on the measured angles of the marble launcher, calculate the initial horizontal and vertical components of the marble’s velocity for each angle, assuming the velocity vector has the same magnitude as you calculated from Part I (4.31 m/s). angle 1: θ = 15° -->initial height 0.027m, horizontal distance 0.145m angle 2: θ = 45° -->initial height 0.027m, horizontal distance 0.209m angle 3: θ = 70° --> initial height 0.027m, horizontal distance 0.118m
- please show the full solution.Based on the measured angles of the marble launcher, calculate the initial horizontal and vertical components of the marble’s velocity for each angle, assuming the velocity vector has the same magnitude as you calculated from Part I (18.54 m/s). angle 1: θ = 15° -->initial height 0.027m, horizontal distance 0.145m angle 2: θ = 45° -->initial height 0.027m, horizontal distance 0.209m angle 3: θ = 70° --> initial height 0.027m, horizontal distance 0.118mAssuming negligible atmospheric friction, a launched projectile has a parabolic path, as shown above. Point Q is the path peak and Points P and R are at the same altitude. Identify the correct relationship of the projectile speeds at the three points. O A. vp = VR < VQ O B. VO < VR < vP OC.Vo< vp = VR O D. VR < VQ < vP O E. Vp < VQ < VR
- During WWI, the Germans had a gun called Big Bertha that was used to shell Paris. The initial velocity of the shell was 1700 m/s at an angle of 55° above the horizontal. Assume it returns to the same height as released. Ignore air resistance. 1. Find the total time in the air for the shell. 2. How far away did the shell hit? 3. Find the shell's velocity at the apex. 4. Find the horizontal and vertical velocity components just when the shell strikes the ground.A cargo plane is moving with a horizontal velocity of v = +248 m/s at a height of y = 990 m above level ground as shown in the figure below when it releases a package. Ignoring air resistance, how much time, in seconds, will it take the package to reach the ground? (Express your answer to the nearest tenth of a second.) S +y +X Dy 7 VyPlease solve the question in detailed, The solution must be correct. Don't use chatgpt,you have to show the diagram also.