A ball is thrown upwards with a speed of 20 m/s off a 5-meter-high balcony. How fast is it falling just before it hitsthe floor below the balcony? We want to show that the answer does not depend on whether we choose +y to beup or to be down. When an object is in free-fall, its acceleration is g=10 m/s²2 down.а.Take +y to be up. VWhat are the values of voy,ay and Ay in this case?b. Take +y to be down. What are the values of voy, avy, and Ay in this case?Only one of the constant acceleration kinematics equations do not involve time. vž = vžy +2 a,Ay. Solve forС.%3Dthe speed |vl just before the ball hits the floor using +y up and using +y down and show you get the sameanswer.

Name: A ball is thrown upwards with a speed of 20 m/s off a 5-meter-high ba
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Description: A ball is thrown upwards with a speed of 20 m/s off a 5-meter-high balcony. How fast is it falling just before it hitsthe floor below the balcony? We want to show that the answer does not depend on whether we choose +y to beup or to be down. When an

Initial speed (u) = 20 m/s Initial height (h) = 5 m g = 10 m/s2 downwards

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A ball is thrown upwards with a speed of 20 m/s off a 5-meter-high balcony. How fast is it falling just before it hits the floor below the balcony? We want to show that the answer does not depend on whether we choose +y to be up or to be down. When an object is in free-fall, its acceleration is g = 10 m/s² down. a. Take +y to be up. What are the values of voy,ɑy and Ay in this case? b. Take +y to be down. What are the values of voy, ay, and Ay in this case? Only one of the constant acceleration kinematics equations do not involve time. vž = vžy + 2 a,Ay. Solve fo С. %3D the speed |v just before the ball hits the floor using +y up and using +y down and show you get the same answer.

A ball is thrown upwards with a speed of 20 m/s off a 5-meter-high balcony. How fast is it falling just before it hits the floor below the balcony? We want to show that the answer does not depend on whether we choose +y to be up or to be down. When an object is in free-fall, its acceleration is g = 10 m/s² down. a. Take +y to be up. What are the values of voy,ɑy and Ay in this case? b. Take +y to be down. What are the values of voy, ay, and Ay in this case? Only one of the constant acceleration kinematics equations do not involve time. vž = vžy + 2 a,Ay. Solve fo С. %3D the speed |v just before the ball hits the floor using +y up and using +y down and show you get the same answer.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Displacement, Velocity and Acceleration

In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.

Linear Displacement

The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.

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Question

A ball is thrown upwards with a speed of 20 m/s off a 5-meter-high balcony. How fast is it falling just before it hits
the floor below the balcony? We want to show that the answer does not depend on whether we choose +y to be
up or to be down. When an object is in free-fall, its acceleration is g=10 m/s²2 down.
а.
Take +y to be up. VWhat are the values of voy,ay and Ay in this case?
b. Take +y to be down. What are the values of voy, avy, and Ay in this case?
Only one of the constant acceleration kinematics equations do not involve time. vž = vžy +2 a,Ay. Solve for
С.
%3D
the speed |vl just before the ball hits the floor using +y up and using +y down and show you get the same
answer.

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