A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 32t + 283. Find its velocity 7 seconds after launch. The velocity of the ball 7 seconds after launch is feet/second. (Round answer to nearest tenth.) o at o at

A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 32t + 283. Find its velocity 7 seconds after launch. The velocity of the ball 7 seconds after launch is feet/second. (Round answer to nearest tenth.) o at o at

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterP: Prologue: Calculator Arithmetic

Section: Chapter Questions

Problem 34SBE: A Skydiver When a skydiver jumps from an airplane, his downward velocity, in feet per second, before...

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A ball is launched straight up in the air from a height of 5 feet. Its velocity (feet/second) t seconds after launch is given by f(t) = - 32t + 283. Find its velocity 7 seconds
after launch.
The velocity of the ball 7 seconds after launch is
feet/second.
(Round answer to nearest tenth.)
o at
o at

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