The velocity (in feet/second) of a projectile t seconds after it is launched from a height of 10 feet is given by v(t)= - 15.4t + 147. Approximate its height after 3 seconds using 6 rectangles. It is approximatley feet. (Round final answer to nearest tenth. Do NOT round until the final answer.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Projectile Motion Approximation Using Rectangles**

The velocity (in feet/second) of a projectile \( t \) seconds after it is launched from a height of 10 feet is given by \( v(t) = -15.4t + 147 \). To approximate its height after 3 seconds using 6 rectangles, follow these steps:

1. Divide the interval [0,3] into 6 equal subintervals. Each subinterval will have a width of \( \Delta t = \frac{3-0}{6} = 0.5 \) seconds.
2. Calculate the velocity, \( v(t) \), at the right endpoint of each subinterval.
3. Use the velocity values to approximate the height by summing the areas of the rectangles.

Calculate each rectangle area:
- For the first interval \([0, 0.5]\): 
  \( v(0.5) = -15.4(0.5) + 147 \)
- For the second interval \([0.5, 1.0]\): 
  \( v(1.0) = -15.4(1.0) + 147 \)
- Continue this process for \( t = 1.5, \ 2.0, \ 2.5, \ and \ 3.0 \).

Summing these areas provides an approximate total displacement, which, when added to the initial height of 10 feet, gives the approximate height after 3 seconds.

**It is approximately \_\_\_\_ feet.**

*(Round the final answer to the nearest tenth. Do NOT round until the final answer.)*
Transcribed Image Text:**Projectile Motion Approximation Using Rectangles** The velocity (in feet/second) of a projectile \( t \) seconds after it is launched from a height of 10 feet is given by \( v(t) = -15.4t + 147 \). To approximate its height after 3 seconds using 6 rectangles, follow these steps: 1. Divide the interval [0,3] into 6 equal subintervals. Each subinterval will have a width of \( \Delta t = \frac{3-0}{6} = 0.5 \) seconds. 2. Calculate the velocity, \( v(t) \), at the right endpoint of each subinterval. 3. Use the velocity values to approximate the height by summing the areas of the rectangles. Calculate each rectangle area: - For the first interval \([0, 0.5]\): \( v(0.5) = -15.4(0.5) + 147 \) - For the second interval \([0.5, 1.0]\): \( v(1.0) = -15.4(1.0) + 147 \) - Continue this process for \( t = 1.5, \ 2.0, \ 2.5, \ and \ 3.0 \). Summing these areas provides an approximate total displacement, which, when added to the initial height of 10 feet, gives the approximate height after 3 seconds. **It is approximately \_\_\_\_ feet.** *(Round the final answer to the nearest tenth. Do NOT round until the final answer.)*
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