A balanced, positive-sequence, Y-connected voltage source with Eab = 480/0° volts is applied to a balanced-A load with ZA = 30/40° 2. The line impedance between the source and load is ZL = 1/85° N for each phase. Calculate the line currents, the A-load currents, and the voltages at the load terminals. %3D

A balanced, positive-sequence, Y-connected voltage source with Eab = 480/0° volts is applied to a balanced-A load with ZA = 30/40° 2. The line impedance between the source and load is ZL = 1/85° N for each phase. Calculate the line currents, the A-load currents, and the voltages at the load terminals. %3D

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.22P: A balanced Y-connected voltage source with Eag=2770volts is applied to a balanced-Y load in parallel...

See similar textbooks

Similar questions

Figure Q2(a) shows a positive sequence three phase circuits. Given a line-to-line voltage at generator, ERY = 415230°V. With assumption that all load impedance are balanced, Zn=Zyb=Zbr= 15 + jl8 2, determine all phase currents at each load and line currents. Include the phasor diagram for all currents in your analysis. R Zry Zyt Figure Q2(a) If the transmission line in three phase circuit at Figure Q2(a) has a impedance of 1+j20 for each phase, determine the phase voltages for each load with using an appropriate analysis. Use phase voltage at generator, ERN as a reference. Then determine the total apparent power, active power and reactive power supplied by the generator.
In Figure 1, the 3-phase source has a line-to-line voltage of 440 volts. The details of the impedances are the following: Z₁ = 36-j15; Z₂ = 40 + /300; Z₂ = 45+j60 ; Z₂ = 75 + jo ; Z5 = 50+j50; Z6 = 20+ j48 2. Determine the following: (a) Line currents: labi, and I (c) Line currents: lar, Ibr, and ICT; (b) Line currents: Iaz, Ibz, and Iczi (d) PT, QT, ST, and pft for the system; (e) W, and W, readings for 2-wattmeter method at lines a and b. Balanced 3-Phase ab-bc-ca source C Figure 1 →laT -Ibr -KT 1 lal ²3 ↓ Ibi 1 Ici la2 lb2 le2ܝ 150 1²₂ OND
Q2) A 13.2-kV single-phase generator supplies power to a load through a transmission line. The load's impedance is Zload = 500 236.87° ohm, and the transmission line's impedance is Zline = 60 253.1° ohm. To reduce transmission line losses to 0.0103 of its losses without using the transformers design and use two transformers T1 between the generator and the transmission line and T2 between the transmission line and the load.
Q2) A 13.2-kV single-phase generator supplies power to a load through a transmission line. The load's impedance is Ztoad 500 236.87° ohm , and the transmission line's impedance is Zine = 60 253.1° ohm. To reduce transmission line losses to 0.0103 of its losses without using the transformers design and use two transformers T1 between the generator and the transmission line and T2 between the transmission line and the load.
(c) In the Y-A system shown in Figure Q2(c), the source is a positive sequence with VRN = 24020° V and phase impedance, Zp = (2 – j3) N. Determine; VRN R Zp VYN Y N Zp ZP VBN B Figure Q2(c) (i) All line voltages, VRY, VYB, and VBr-. (ii) All line currents, IR, Iy and Ig. (iii) Total real power absorbs by the loads.
2. A single-phase are distributor AB is fed from end A and has a total impedance of (0.3-0.3) ohm. At the far end, the voltage V-240V and the current is 100A at a p.f. of 0, 8 lagging. At the mid-point M. a current of 100 A is tapped at a p... of 0.6 lagging with reference to the voltage V_{M} at the midi-point. Calculate the supply voltage V Lambda j sending current I_{N} and the phase angle between V_{A} and V_{E}
Q4/For the three-phase power network shown in Figure. the various components are: GI: 100 MVA, 0.30 pu reactance. G2: 60 MVA, 0.18 pu reactance. Transformers (cach): 50 MVA, 0.10 pu reactance. Inductive reactor X: 0.20 pu on a base of 100 MVA. Lines (each): 80 ohms (reactive); neglect resistance. with the network initially unloaded and a line voltage of 110 kV, a symmetrical short circuit occurs at midpoint E of line 2. Calculate the short circuit MVA to be interrupted by the circuit breakers A and B at the ends of the line. T3 38 L1 L2 G2 Bas 12 T4 Bus
3. A three phase source, 4-wire having a per phase voltage of 230V. An unbalanced load is connected to the three phase source. The load impedances are: Zan = 15253.13° N; Zbn = 152-53.13° ; Zen = 150° Assuming negative sequence and the reference is the phase voltage "a", determine: a. the line current "a" b. the line current “b” c. the line current "c". d. the total real power e. the total reactive power f. the total apparent power g. the overall power factor h. the neutral current.
In the three-phase system shown in the figure, phase a is on no load and phases b and C are short-circuited to ground Ia = 0 In Ie The following currents are given: I, = 91.656 Z160.9° I, = 60.006 Z90° Find the symmetrical components of current 1,, I, and 1, .
(b) A symmetrical delta-connected 415V three-phase supply is feed to an asymmetrical delta- connected load as shown in Figure Q2(b). Assume that it is a RYB sequence. The impedances of the load are ZrY = 50 + j50 N , ZYB = 150 + j0 N and ZBr = 50 –j50 N. jos (i) Determine and draw the phasor diagram of phase currents in the load. (ii) Determine and draw the phasor diagram of line currents in the system.
In a three-phase system the per-unit phase voltages are 100° , Vôn = 0.8Z180° Van 0.920° , Von = 0.92 - а What are the per-unit symmetrical components V0) and V)? Express in polar notation.
A balanced delta connected load of 15 + J18 Q per phase is connected at the end of a three-phase line as shown in Figure 2.25. The line impedance is 14-j2 Q per phase. The line is supplied from a three-phase source with a line-to-line voltage of 207.85 V rms. Taking Van as reference, determine the following: (a) Current in phase a. (b) Total complex power supplied from the source. (c) Magnitude of the line-to-line voltage at the load terminal. 1+j2N wwwm VL = 207.85 V bo Co- FIGURE 2.25 Circuit for Problem 2.13. b a 15+j18 N