{(a, b, c) : 3a – 26 – c = 0} of RŠ. It can be shown that Consider the subspace W = S = {(1, 1,1), (-1,–4, 5)} is an orthogonal basis for W. Given that the orthogonal projection of (1,2, 3) onto W is (a, b, c), U = find the value of the number a. find the value of the number b. find the value of the number c.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Hi, I need help with this Linear Algebra problem, please. I've tried 2.538, -10.392, & -1.165, but that doesn't appear to be correct. Any help is greatly appreciated. Thank you!

Consider the subspace W = {(a, b, c) : 3a – 2b – c= 0} of R³. It can be shown that
S = {(1,1,1), (-1,–4,5)} is an orthogonal basis for W. Given that the orthogonal projection of (1, 2, 3)
onto W is
(a, b, c),
U =
find the value of the number a. find the value of the number b. find the value of the number c.
Transcribed Image Text:Consider the subspace W = {(a, b, c) : 3a – 2b – c= 0} of R³. It can be shown that S = {(1,1,1), (-1,–4,5)} is an orthogonal basis for W. Given that the orthogonal projection of (1, 2, 3) onto W is (a, b, c), U = find the value of the number a. find the value of the number b. find the value of the number c.
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