A B B S 1 You go to the lab to carry out an extraction. Solute A is the desired product How would you go about selecting an appropriate extraction solvent S2 to extract product A from solution in Solvent S1. – (Choose all that applies) O S2 should be chemically inert to product A O S2 should be immiscible to S1 O S2 should dissolve product B O S2 should dissolve both product A and B O Product A should have a higher solubility in S2 relative to S1

A B B S 1 You go to the lab to carry out an extraction. Solute A is the desired product How would you go about selecting an appropriate extraction solvent S2 to extract product A from solution in Solvent S1. – (Choose all that applies) O S2 should be chemically inert to product A O S2 should be immiscible to S1 O S2 should dissolve product B O S2 should dissolve both product A and B O Product A should have a higher solubility in S2 relative to S1

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter5: Distillation

Section: Chapter Questions

Problem 7Q: In fractional distillation, liquid can be seen running from the bottom of the distillation column...

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2 Trial 1: [4] Volume of NaOH, dispensed (mL) Trial 1: [5] Molar concentration of NaOH (mol/L) Trial 2: [4] Volume of NaOH, dispensed (mL) How Trial 2: [5] Molar concentration of NaOH (mol/L) Trial 3: [4] Volume of NaOH, dispensed (mL) Trial 3: [5] Molar concentration of NaOH (mol/L)
A. Standardlzatlon of thlosulfate solutlon Trial 1 Trial 2 Trial 3 Initial volume of thiosulfate (mL) 0.00 20.05 2.3 Final volume of thiosulfate (mL) 20.05 40.05 22.15 Volume of thiosulfate used (mL) Molarity of thiosulfate Average Molarity of thiosulfate Calculate the molarity of the thiosulfate solution using the formula: 6 mmol S20,²- 1 mmol 10, Ms,0,2- 0.004167 M 10,- 20.00 ml Vol S20,²- used (mL)
Concentration of the KSCN stock solution, M Volume of the KSCN stock solution, mL Initial molar concentration of SCN in a 50-ml flask, M PART A. Establishing the Beer's Law Coefficient: blank 0 0 solution 2 1.00×10-³ 2.00 solution 3 1.00×10-3 5.00 solution 4 1.00×10-³ 10.00 solution 5 1.00-10-3 15.00
1. A 50.00 mL stock CaCl2 solution was diluted with water in a 250.0-mL volumetric flask. A 25.00 mL aliquot of this was further diluted to a final volume of 100.0 mL. Finally, 20.00-mL aliquot of the resulting solution was analyzed and found to contain 0.1500 M CaCh2 Solve for the concentration of the stock solution in M. 2. A 50.00 mL stock CaCl2 solution was diluted with water in a 250.0-mL volumetric flask. A 25.00 mL aliquot of this was further diluted to a final volume of 100.0 mL. Finally, 20.00-mL aliquot of the resulting solution was analyzed and found to contain 0.1200 g CaCl2 Solve for %w/v CaCl2 in the stock solution.
Choose the situation below that would result in a AHsolution near 0 A B O C OD DE O When IAH solvent! >> AHsolutel O When IAHsolutel > AHhydration! O When IAHsolutel
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L.5 Hi Experts! Can you please help me complete the tables? please kindly also include some sample calculations. THANK YOUUU SOO MUCHH!! Results (GIVEN) Solvent Trial Volume of NaOH (mL) Concentration of NaOH (M) Volume of Solution (mL) Concentration of Solution (M) Water 1 15.6 0.4664 10 2 15.4 0.4664 10 Average Ether 1 31.9 0.0823 10 2 31.8 0.0823 10 Average Table 1. Data for 1 M Acetic acid. Solvent Trial Volume of NaOH (mL) Concentration of NaOH (M) Volume of Solution (mL) Concentration of Solution (M) Water 1 7.6 0.4664 10 2 7.7 0.4664 10 Average Ether 1 20.2 0.0823 10 2 18.3 0.0851 10 Average Table 2. Data for 0.5 M Acetic acid. Solvent Trial Volume of NaOH (mL) Concentration of NaOH (M) Volume of Solution (mL)…
5. From the stock solutions of 1.00-mol L acetic acid and 1.00-mol L of sodium acetate, six solutions were prepared with the acetic acid and acetate concentrations shown in the table below. The pk of acetic acid is 4.756. [Acetic acid). [Acetate). Final volume, Solutio mol L mol L ml A. 0.10 100 0.0000351 100 0.10 0.10 100 0.010 0.010 100 0.10 0.15 100 0.15 0.10 100 -1 Determine the volume of the stock solutions of 1.00-mol Lacetic acid and 1.00-mol L of sodium acetate needed to prepare the solutions. Write your answer in the table below. a. Vol. acetic acid, ml Vol. of acetate, ml Solution A b. Calculate for the initial pH of the solutions and write the pH in the table below. Solution Initial pH A Which solution(s) have the same pH? C.
Can you help me find the theoretical yield of precipitate in trial 1 & 2
QUESTION 4 To prevent inclusion from occurring during precipitation, the technique to follow is I. fiter precipitate with less porous paper II. crystal growth be made to occur more slowly III. use of dilute analyte with concentrated precipitant IV. addition of soluble electrolyte O lonly IV only O I| & IV O I & III Il only
What volume, in L, of 0.108M aluminum carbonate solution is needed to react with 35.86g solid potassium hydroxide? A Click Submit to complete this assessment. mm10451 quiz6 2.pdf UI Online - Doc_....pdf AcroRdrDC_210...dmg Chapter 6 study. 2,005 étv W MacBook Air D00 000 F4 DII DD F5 F6 F7 F8