(a) An activated sludge system is to treat wastewater from a population of 9,500 PE. The wastewater enters a primary clarifier with BOD5 of 350 mg/L. The primary clarifier removes 40% of the BOD5. A complete-mix reactor is to be used and from a pilot plant study, the Y and ka values are 0.5 kg/kg and 0.05 per day, respectively. Assume an MLSS concentration of 4,000 mg/L and a mean cell residence time of 10 days. The effluent of the treatment system should comply with the Standard A based on the Environmental Quality Sewage Regulations (2009). Determine: i. 11. 111. Concentration of BOD5 that enter the aeration tank. ii. Dimensions of the aeration tank provided there are two rectangular tanks. Use width-to-length ratio of 1:2 with water depth of 3.5 m. Food-to-microorganisms ratio
(a) An activated sludge system is to treat wastewater from a population of 9,500 PE. The wastewater enters a primary clarifier with BOD5 of 350 mg/L. The primary clarifier removes 40% of the BOD5. A complete-mix reactor is to be used and from a pilot plant study, the Y and ka values are 0.5 kg/kg and 0.05 per day, respectively. Assume an MLSS concentration of 4,000 mg/L and a mean cell residence time of 10 days. The effluent of the treatment system should comply with the Standard A based on the Environmental Quality Sewage Regulations (2009). Determine: i. 11. 111. Concentration of BOD5 that enter the aeration tank. ii. Dimensions of the aeration tank provided there are two rectangular tanks. Use width-to-length ratio of 1:2 with water depth of 3.5 m. Food-to-microorganisms ratio
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Subject watewater engineering
![(a)
An activated sludge system is to treat wastewater from a population of 9,500
PE. The wastewater enters a primary clarifier with BOD5 of 350 mg/L. The
primary clarifier removes 40% of the BOD5. A complete-mix reactor is to be
used and from a pilot plant study, the Y and kå values are 0.5 kg/kg and 0.05
per day, respectively. Assume an MLSS concentration of 4,000 mg/L and a
mean cell residence time of 10 days. The effluent of the treatment system
should comply with the Standard A based on the Environmental Quality
Sewage Regulations (2009).
Determine:
i.
ii.
iii.
Concentration of BOD5 that enter the aeration tank.
ii. Dimensions of the aeration tank provided there are two rectangular
tanks. Use width-to-length ratio of 1:2 with water depth of 3.5 m.
Food-to-microorganisms ratio](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe7364e8-57ac-4da3-a42b-60f0e2c17090%2F8a538e81-0210-44de-bda4-d979199d3eac%2Fbuqd6et_processed.png&w=3840&q=75)
Transcribed Image Text:(a)
An activated sludge system is to treat wastewater from a population of 9,500
PE. The wastewater enters a primary clarifier with BOD5 of 350 mg/L. The
primary clarifier removes 40% of the BOD5. A complete-mix reactor is to be
used and from a pilot plant study, the Y and kå values are 0.5 kg/kg and 0.05
per day, respectively. Assume an MLSS concentration of 4,000 mg/L and a
mean cell residence time of 10 days. The effluent of the treatment system
should comply with the Standard A based on the Environmental Quality
Sewage Regulations (2009).
Determine:
i.
ii.
iii.
Concentration of BOD5 that enter the aeration tank.
ii. Dimensions of the aeration tank provided there are two rectangular
tanks. Use width-to-length ratio of 1:2 with water depth of 3.5 m.
Food-to-microorganisms ratio
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