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a) Adiabatic Operation. Plot X, Xe, p, T, and the rate of disappearance as a function of V up to V = 40 dm³. Explain why the curves look the way they do.

a) Adiabatic Operation. Plot X, Xe, p, T, and the rate of disappearance as a function of V up to V = 40 dm³. Explain why the curves look the way they do.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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The gas-phase reversible reaction AZB is carried out under high pressure in a packed-bed reactor with pressure drop. The feed consists of both inerts I and Species A with the ratio of inerts to the species A being 2 to 1. The entering molar flow
Transcribed Image Text:The gas-phase reversible reaction AZB is carried out under high pressure in a packed-bed reactor with pressure drop. The feed consists of both inerts I and Species A with the ratio of inerts to the species A being 2 to 1. The entering molar flow
rate of A is 5 mol/min at a temperature of 300 K and a concentration of 2 mol/dm³. Work this problem in terms of volume. Hint: V = W/PB, ₁ = PBA · Additional information: FA0 = 5.0 mol/min ΑΟ Cao =2mol/dm3 C=2 CAO C₁ =18 cal/mol/K CPA = 160 cal/mol/K E = 10,000 cal/mol AHRX = -20,000 cal/mol Rx Kc = 1,000 at 300 K CPB = 160 cal/mol/K To = 300 K T₁ = 300 K k₁ = 0.1 min¯¹ at 300 K Ua = 150 cal/dm³/min/K Tao = 300 K V = 40 dm³ -3 apb=0.02 dm¯ Coolant mc = 50 mol/min CP Cool = 20 cal/mol/K PB = 1.2 kg/dm³ (a) Adiabatic Operation. Plot X, Xê, p, T, and the rate of disappearance as a function of V up to V = 40 dm³. Explain why the curves look the way they do.
Transcribed Image Text:rate of A is 5 mol/min at a temperature of 300 K and a concentration of 2 mol/dm³. Work this problem in terms of volume. Hint: V = W/PB, ₁ = PBA · Additional information: FA0 = 5.0 mol/min ΑΟ Cao =2mol/dm3 C=2 CAO C₁ =18 cal/mol/K CPA = 160 cal/mol/K E = 10,000 cal/mol AHRX = -20,000 cal/mol Rx Kc = 1,000 at 300 K CPB = 160 cal/mol/K To = 300 K T₁ = 300 K k₁ = 0.1 min¯¹ at 300 K Ua = 150 cal/dm³/min/K Tao = 300 K V = 40 dm³ -3 apb=0.02 dm¯ Coolant mc = 50 mol/min CP Cool = 20 cal/mol/K PB = 1.2 kg/dm³ (a) Adiabatic Operation. Plot X, Xê, p, T, and the rate of disappearance as a function of V up to V = 40 dm³. Explain why the curves look the way they do.
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