(a) A statistical test at significance level a = 0.05 has power 0.78. What are the probabilites of Type I and Type II errors for thistest? Give your answers to two decimal places.P (Type I error) =P (Type II error) =(b) A statistical test at the a = 0.01 level has probability 0.14 of making a Type II error when a specific alternative is true. Whatis the power of the test against this alternative? Give your answer to two decimal places.power:

(a) Given,Level of significance, α = 0.05Power = 0.78

Answered: (a) A statistical test at significance…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the claim that the average IQ score is less than 100 at the .01 significance level. You determine the hypotheses are: Ho: μ=100 H1:μ<100H You take a simple random sample of 79 individuals and find the mean IQ score is 98.3, with a standard deviation of 15.3. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ score is less…
Professor Nord stated that the mean score on the final exam from all the years he has been teaching is a 79%. Colby was in his most recent class, and his class’s mean score on the final exam was 82%. Colby decided to run a hypothesis test to determine if the mean score of his class was significantly greater than the mean score of the population. α = .01. What is the mean score of the population? What is the mean score of the sample? Is this test one-tailed or two-tailed? Why?
Scores on an IQ test are normally distributed. A sample of 25 IQ scores had variance of 64. The developer of the test claims that the population standard deviation is 15. Do these data provide sufficient evidence to significance? Use α=0.05α=0.05 . Answer the following questions. (a) What is the parameter? . (input as "mean", "standard deviation", "variance" or "proportion") (b) Determine if the alternative hypothesis is "right", "left" or "two-tailed" test. (input as "right", "left" or "two-tailed") (c) Test by using a confidence interval. Round confidence interval to nearest thousandth. (e.g. 0.1345 would be entered as 0.135) between ( and ) (d) State conclusion.: There is (input as "sufficient" or "insufficient") to (input as "conclude" or "reject") to conclude that the population standard deviation of IQ test is 15.
You wish to test the following claim (Ha) at a significance level of α=0.01. Ho:μ=88.9Ha:μ>88.9 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=17 with mean ¯x=98.1 and a standard deviation of s=18.9 What is the test statistic for this sample? test statistic = Round to 3 decimal places What is the p-value for this sample? p-value = Round to 4 decimal places.
You wish to test the following claim (Ha) at a significance level of a = 0.001. Ho:µ = 60.5 Ha:µ + 60.5 You believe the population is normally distributed and you know the standard deviation is o = 11.1 You obtain a sample mean of M = 56.9 for a sample of size n = 39. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is. O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 60.5. O There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 60.5. O The sample data support the claim that the population mean is not equal to 60.5. O…
Can you please help me with this statistics last math problem? Thank you!
1.A chi-square test for independence is being used to evaluate the relationship between two variables, one of which is classified into 2 categories and the second of which is classified into 4 categories. What is the df value for the chi-square statistic? a. df = 2 b. df = 6 c. df = 7 d. df = 3

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