(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper globes with mass m = 0.190 g to strings of length L as shown in the figure.LAmmBoth globes have the same charge of 6.40 nC, and are in static equilibrium when.25Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the globes. Find an equation for the distance between the two globes in termsof L and 0, and use this expression in your Coulomb force equation. m=5.40°. What is L (in m)? Assume the strings are massless.(b) What If? The charge on both globes is increased until each string makes an angle of 0: 10.8° with the vertical. If both globes have the same electric charge, what isthe charge (in nC) on each globe in this case?18.6XUse the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nC

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(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper globes with mass m = 0.190 g to strings of length L as shown in the figure. Both globes have the same charge of 6.40 nC, and are in static equilibrium when = 5.40°. What is L (in m)? Assume the strings are massless. X 25 Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the globes. Find an equation for the distance between the two globes in terms of L and 8, and use this expression in your Coulomb force equation. m (b) What If? The charge on both globes is increased until each string makes an angle of 0 = 10.8° with the vertical. If both globes have the same electric charge, what is the charge (in nC) on each globe in this case? 18.6 X Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nC

(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper globes with mass m = 0.190 g to strings of length L as shown in the figure. Both globes have the same charge of 6.40 nC, and are in static equilibrium when = 5.40°. What is L (in m)? Assume the strings are massless. X 25 Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the globes. Find an equation for the distance between the two globes in terms of L and 8, and use this expression in your Coulomb force equation. m (b) What If? The charge on both globes is increased until each string makes an angle of 0 = 10.8° with the vertical. If both globes have the same electric charge, what is the charge (in nC) on each globe in this case? 18.6 X Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nC

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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(a) A physics lab instructor is working on a new demonstration. She attaches two identical copper globes with mass m = 0.190 g to strings of length L as shown in the figure.
L
A
m
m
Both globes have the same charge of 6.40 nC, and are in static equilibrium when
.25
Draw a free-body diagram, apply Newton's second law for a particle in equilibrium to one of the globes. Find an equation for the distance between the two globes in terms
of L and 0, and use this expression in your Coulomb force equation. m
=
5.40°. What is L (in m)? Assume the strings are massless.
(b) What If? The charge on both globes is increased until each string makes an angle of 0: 10.8° with the vertical. If both globes have the same electric charge, what is
the charge (in nC) on each globe in this case?
18.6
X
Use the same reasoning as in part (a), only now, use the length found in part (a) and the new angle to solve for the charge. nC

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