(a) A heavy cord is vibrating in its fundamental mode and under a tension of 205 N. When a vibrating tuning fork is placed near the cord, a beat frequency of 4.90 Hz is heard. If the cord is 1.50 m long and has a mass of 0.0150 kg, determine the possible frequencies (in Hz) of the tuning fork. (Round your answers to at least the nearest integer.) lower frequency Hz higher frequency Hz (b) The tension in the cord is now adjusted such that when it vibrates in the fundamental mode, no beats occur when the tuning fork is brought near. Given the two possible tuning fork frequencies found above, determine the two possible tensions (in N) in the cord that will allow this.

(a) A heavy cord is vibrating in its fundamental mode and under a tension of 205 N. When a vibrating tuning fork is placed near the cord, a beat frequency of 4.90 Hz is heard. If the cord is 1.50 m long and has a mass of 0.0150 kg, determine the possible frequencies (in Hz) of the tuning fork. (Round your answers to at least the nearest integer.) lower frequency Hz higher frequency Hz (b) The tension in the cord is now adjusted such that when it vibrates in the fundamental mode, no beats occur when the tuning fork is brought near. Given the two possible tuning fork frequencies found above, determine the two possible tensions (in N) in the cord that will allow this.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: frequency of its fundamental mode? (b) If the string is plucked transversely and is then touched at…

Q: One of the harmonic frequencies for a particular string under tension is 321.00 Hz. The next higher…

A: Given Data: Harmonic frequency under tension is 321.00 Hz The next harmonic frequency is 327.42 Hz

Q: The A string of a violin has a linear density of 0.60 g/m and an effective length of 330 mm. (a)…

A: From the question, it is given that- Linear mass density of string: μ = 0.60 g/m = 0.60×10-3 kg/m…

Q: A steel wire with mass 25.4 g and length 1.30 m is strung on a bass so that the distance from the…

Q: A stretched string fixed at each end has a mass of 47.0 g and a length of 8.20 m. The tension in the…

A: Visualize the Problem:

Q: The A string on a violin has a fundamental frequency of 440 Hz. The length of the vibrating portion…

Q: and a length of 7.00 m. The tension in the string is 44.0 N. (a) Determine the positions of the…

A: Given, mass=44gram Distance=7m Tension=47N

Q: (a) A heavy cord is vibrating in its fundamental mode and under a tension of 195 N. When a vibrating…

A: The given values are,

Q: Problem 3. A wave traveling on a Slinky® that is stretched to 4 m takes 2.4 s to travel the length…

A: Distance traveled:d=2L=2×4=8 mt=2.4 sNumber of nodes=4Number of antinodes=3

Q: A cord of length 1.75 m is fixed at both ends. Its mass per unit length is 1.2 x 10-3 kg/m and the…

A: The given values are, L=1.75 mμ=mL=1.2×10-3 kg/mT=15 N

Q: A stretched string fixed at each end has a mass of 48.0 g and a length of 8.60 m. The tension in the…

A: When a stretched string fixed at both its ends is plucked, it starts vibrating, and a standing wave…

Q: 3.20 The fundamental frequency of an open organ pipe corresponds to the A above middle C (440 Hz on…

Q: A guitar player tunes the fundamental frequency of a guitar string to 450 Hz. (a) What will be the…

Q: The D-string on a properly tuned guitar produces a tone with a fundamental frequency of 146.8Hz. The…

A: Given thatThe fundamental frequency (f) =146.8 HzThe oscillating length of a D-string on a certain…

Q: A wire with mass 50 g is stretched so that its ends are tied down at points 90 cm apart. The wire…

A: GivenMass of wire (M) = 50 g = 50 ×10-3 kg =5×10-2 kgLength of the wire (l) = 90 cm = 90 × 10-2 m =…

Q: The D-string on a properly tuned guitar produces a tone with a fundamental frequency of 146.8 Hz.…

Q: A piano tuner stretches a steel piano wire with a tension of 800 NN. The steel wire is 0.400 mm long…

A: Given:- A piano tuner stretches a steel piano wire with Tension T = 800 N The length of the steel…

Q: A string of mass 35 g and length 3.0 m is clamped at the ends. It is found that standing waves can…

A: The mass of the string is, m=35 g=0.035 kg. The length of the string is, L= 3 m. The initial…

Q: A cord with a mass of 0.65kg is stretched between two supports 8.0 m apart. If the tension in the…

A: Step 1:Step 2:Step 3:Step 4:

Q: wo identical piano wires have a fundamental frequency of 600 Hz when kept under the same tension.…

A: Fundamental frequency of vibrations produced on a string under tension is given by the expression…

Q: A piano string is 1.10 meters long and has a mass of 0.00900 kilograms. How much tension must the…

Q: A thin 1.0-m metal rod sustains a longitudinal standing wave with vibration antinodes at each end of…

A: Given that,length of the rod (l) = 1mdensity of metal rod Young's modulus of the metal

Q: A string is fixed at both ends and is vibrating at 136 Hz, which is its third harmonic frequency.…

Q: A stretched string fixed at each end has a mass of 40.0g and a length of 8.00m. The tension in the…

Q: The D-string on a properly tuned guitar produces a tone with a fundamental frequency of 146.8 Hz.…

A: Given that The fundamental frequency (f) =146.8 Hz The oscillating length of a D-string on a certain…

Q: A string with a mass ? = 8.00? and a length ? = 5.00 ? has one end attached to a wall; the other end…

A: The speed of the wave in the string can be expressed as v=Tμ=mgms/L=4 kg9.8 m/s20.008 kg/5 m=156.524…

Q: Problem 4: The D-string on a properly tuned guitar produces a tone with a fundamental frequency of…

A: Using principles of wave in a string we can solve the problem as solved below. Note - AS per our…

Q: A steel wire in a piano has a length of 0.520 m and a mass of 4.600 x 10 kg. To what tension must…

A: From the fundamental frequency formula , We know that , f = nv/2L ----> f^2 = v^2/4L^2 and We…

Q: When a string that is 2m long is connected between two supports and vibrated at 176 Hz it is…

Concept explainers

Electromagnetic Waves

Electromagnetic waves are waves that consist of magnetic field and electric field components perpendicular to each other. These field components are also perpendicular to the direction of propagation of the wave.

Question

(a) A heavy cord is vibrating in its fundamental mode and under a tension of 205 N. When a vibrating tuning fork is placed near the cord, a beat frequency of
4.90 Hz is heard. If the cord is 1.50 m long and has a mass of 0.0150 kg, determine the possible frequencies (in Hz) of the tuning fork. (Round your answers
to at least the nearest integer.)
lower
frequency
Hz
higher
frequency
Hz
(b) The tension in the cord is now adjusted such that when it vibrates in the fundamental mode, no beats occur when the tuning fork is brought near. Given the
two possible tuning fork frequencies found above, determine the two possible tensions (in N) in the cord that will allow this.
lower tension
higher tension
N

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

A steel wire with mass 21.7 g and length 1.30 m is strung on a bass so that the distance from the nut to the bridge is 1.10 m. (a) Compute the linear density of the string.(b) What velocity wave on the string will produce the desired fundamental frequency of the E1 string, 41.2 Hz?(c) Calculate the tension required to obtain the proper frequency.(d) Calculate the wavelength of the string's vibration.(e) What is the wavelength of the sound produced in air? (Assume the speed of sound in air is 343 m/s.)
(a) A heavy cord is vibrating in its fundamental mode and under a tension of 210 N. When a vibrating tuning fork is placed near the cord, a beat frequency of 4.90 H is heard. If the cord is 1.50m long and has a mass of 0.0150 kg, determine the possible frequencies (in Hz) of the tuning fork. (Round your answers to at least the nearest integer.) lower frequency Hz higher frequency Hz (b) The tension in the cord is now adjusted such that when it vibrates in the fundamental mode, no beats occur when the tuning fork is brought near. Given the two possible tuning fork frequencies found above, determine the two possible tensions (in N) in the cord that will allow this. lower tension higher tension
Two identical piano wires have a fundamental frequency of 555 Hz when kept under the same tension. What fractional increase in the tension of one wire will lead to the occurrence of 7 beats/s when both wires oscillate simultaneously?
A 2.00-m-long wire having a mass of 0.100 kg is fixed at both ends. The tension in the wire is maintained at 20.0 N. (a) What are the frequencies of the first three allowed modes of vibration (standing waves)? (b) If a node is observed at a point 0.400 from one end, in what mode and with what frequency is it vibrating? (c) If this wire can be used to create a sound wave as part of a musical instrument, what is the frequency and wavelength of the sound wave created if the string is oscillating in its fundamental mode?
Transverse waves with a speed of 46.5 m/s are to be produced on a stretched string. A 5.40-m length of string with a total mass of 0.0600 kg is used. (a) What is the required tension in the string? (b) Calculate the wave speed in the string if the tension is 8.00 N. m/s
A stretched string fixed at each end has a mass of 37.0 g and a length of 9.00 m. The tension in the string is 44.0 N. (a) Determine the positions of the nodes and antinodes for the third harmonic. (Enter your answers from smallest to largest distance from one end of the string.)nodes: ?m ? m ? m ? m antinodes: ? m ?m ?m (b) What is the vibration frequency for this harmonic? ?Hz
A steel wire in a piano has a length of 0.900 m and a mass of 3.800 ✕ 10^-3 kg. To what tension must this wire be stretched so that the fundamental vibration corresponds to middle C (fC = 261.6 Hz on the chromatic musical scale)? Needs Complete typed solution with 100 % accuracy.
The frequency of a musical note is 320 Hz. If an organ pipe is open at one end and closed at the other, what length must it have for its fundamental mode to produce this note? ☐ m
An organ pipe (L = 3.5 m) is closed at one end. Compute the wavelengths and frequencies of the first three modes of resonance. Assume the speed of sound is v = 343.00 m/s. fi : Hz f3 Hz f5 = Hz
A 1.6 m long string fixed at both ends vibrates at resonant frequency of 780 Hz and 1040 Hz, with no other resonant frequency between these values. The tension in the string is 1200 N. (a) Calculate the fundamental frequency of the string. (b) Calculate the mass of the string.