(a) A 1.00 cm-high object is placed 3.15 cm to the left of a converging lens of focal length 7.95 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position ✓cm in front of the second lens ✔✔✔ height 6.6 3.07 x Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? Ⓒupright O inverted Is the image real or virtual? O real virtual (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position? distance direction 10.15 to the left ✓✓ x cm

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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(a) A 1.00 cm-high object is placed 3.15 cm to the left of a converging lens of focal length 7.95 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
position
cm in front of the second lens ✔
height
6.6
3.07
x
Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm
Is the image inverted or upright?
Ⓒupright
O inverted
Is the image real or virtual?
O real
O virtual
(b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original
position?
distance
direction
10.15
to the left
✔
X cm
Transcribed Image Text:(a) A 1.00 cm-high object is placed 3.15 cm to the left of a converging lens of focal length 7.95 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position cm in front of the second lens ✔ height 6.6 3.07 x Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? Ⓒupright O inverted Is the image real or virtual? O real O virtual (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position? distance direction 10.15 to the left ✔ X cm
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