A 96-mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoid at its center. The coil's resistance is 9.9 ohms. The mutual inductance of the coil and solenoid is 31 µH. At a given instant, the current in the solenoid is 540 mA and is decreasing at the rate of 2.5 A/s. At the given instant, what is the magnitude of the induced current in the coil? (µ_0 = 4Tt × 10^-7 T • m/A) * Q

icon
Related questions
Question
A 96-mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil
is tightly wound around the solenoid at its center. The coil's resistance is 9.9 ohms. The mutual
inductance of the coil and solenoid is 31 µH. At a given instant, the current in the solenoid is
540 mA and is decreasing at the rate of 2.5 A/s. At the given instant, what is the magnitude of
the induced current in the coil? (µ_0 = 4Tt x 10^-7 T•m/A) *
Transcribed Image Text:A 96-mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoid at its center. The coil's resistance is 9.9 ohms. The mutual inductance of the coil and solenoid is 31 µH. At a given instant, the current in the solenoid is 540 mA and is decreasing at the rate of 2.5 A/s. At the given instant, what is the magnitude of the induced current in the coil? (µ_0 = 4Tt x 10^-7 T•m/A) *
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions