A 81 kg skydiver can be modeled as a rectangular "box" with dimensions 24 cm × 47 cm × 170 cm. If he falls feet first, his drag coefficient is 0.80.
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![A 81 kg skydiver can be modeled as a rectangular "box" with
dimensions 24 cm × 47 cm × 170 cm. If he falls feet first, his drag
coefficient is 0.80.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce367b30-70a5-48e4-a959-d9e1e1aaa8b8%2F6a04d616-8f1d-40e4-a2e5-8da13ce3e4f1%2Fua9aclr_processed.jpeg&w=3840&q=75)
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- A mass, m is on an incline of angle as shown. It is connected via a string to a pulley of moment of inertia, I, and radius, R. (a) How fast will it be moving when it has moved a distance D down the incline? (b) Now assume that there is friction between the mass and the incline, pk. How fast will it be moving now when it has moved a distance D down the incline?Ch23,P57R r M
- Part B Which of the four drawings is a correct force diagram for this problem? (Figure 2) a b C Submit Request Answer Choose a coordinate system for each body Newton's 2nd law, F = mã, is a vector equation. To add or subtract vectors it is often easiest to decompose each vector into components. Whereas a particular set of vector components is only valid in a particular coordinate system, the vector equality holds in any coordinate system, giving you freedom to pick a coordinate system that most simplifies the equations that result from the component equations. It's generally best to pick a coordinate system where the acceleration of the system lies directly on one of the coordinate axes. If there is no acceleration, then pick a coordinate system with as many unknowns as possible along the coordinate axes. Vectors that lie along the axes appear in only one of the equations for each component, rather than in two equations with trigonometric prefactors. Note that it is sometimes…R-18.0 2 R 6.00 2 R 3.00 2 9.0 V 3.0 V 13answer d please