A +8.75 µC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 µC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85 x 108 N/C is directed parallel Part A to the wire, as shown in the figure (Figure 1). Find the tension in the wire. Express your answer with the appropriate units. HA ? T = Value Submit Request Answer Part B What would the tension be if both charges were negative? Express your answer with the appropriate units. T = Value Submit Request Answer
A +8.75 µC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 µC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85 x 108 N/C is directed parallel Part A to the wire, as shown in the figure (Figure 1). Find the tension in the wire. Express your answer with the appropriate units. HA ? T = Value Submit Request Answer Part B What would the tension be if both charges were negative? Express your answer with the appropriate units. T = Value Submit Request Answer
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![**Physics Problems on Electric Forces and Tension**
**Problem Description:**
A +8.75 µC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 µC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85 × 10³ N/C is directed parallel to the wire, as shown in the figure (Figure 1).
**Part A:**
Find the tension in the wire.
- Express your answer with the appropriate units.
**Answer Input:**
\[ T = \, \boxed{\text{Value}} \, \text{N} \]
- [Submit Button]
- [Request Answer Button]
**Part B:**
What would the tension be if both charges were negative?
- Express your answer with the appropriate units.
**Answer Input:**
\[ T = \, \boxed{\text{Value}} \, \text{N} \]
- [Submit Button]
- [Request Answer Button]
**Figure 1:**
- A diagram illustrating the arrangement of charges and the electric field. The +8.75 µC charge (represented by a red sphere) and the -6.50 µC charge (represented by a blue sphere) are separated by a distance of 2.50 cm. An electric field \( E \) is shown as a pink arrow pointing to the right, indicating the direction of the field.
**Figure Explanation:**
- The diagram shows two point charges tied together by a wire. The positive charge (+8.75 µC) is on the right, and the negative charge (-6.50 µC) is on the left. They are 2.50 cm apart. An external electric field \( E \) with a magnitude of \( 1.85 \times 10^3 \, \text{N/C} \) is directed to the right, parallel to the wire connecting the charges.
**Note:**
For accurate calculation, consider both the electric force due to the charges and the external electric field when determining the tension in the wire.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F474861d3-aaf1-4b4c-afe2-e250091335e4%2Fa56e3f8a-ec1d-4d4a-90fa-8d1e56cc0869%2Fcf56unm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Physics Problems on Electric Forces and Tension**
**Problem Description:**
A +8.75 µC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 µC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85 × 10³ N/C is directed parallel to the wire, as shown in the figure (Figure 1).
**Part A:**
Find the tension in the wire.
- Express your answer with the appropriate units.
**Answer Input:**
\[ T = \, \boxed{\text{Value}} \, \text{N} \]
- [Submit Button]
- [Request Answer Button]
**Part B:**
What would the tension be if both charges were negative?
- Express your answer with the appropriate units.
**Answer Input:**
\[ T = \, \boxed{\text{Value}} \, \text{N} \]
- [Submit Button]
- [Request Answer Button]
**Figure 1:**
- A diagram illustrating the arrangement of charges and the electric field. The +8.75 µC charge (represented by a red sphere) and the -6.50 µC charge (represented by a blue sphere) are separated by a distance of 2.50 cm. An electric field \( E \) is shown as a pink arrow pointing to the right, indicating the direction of the field.
**Figure Explanation:**
- The diagram shows two point charges tied together by a wire. The positive charge (+8.75 µC) is on the right, and the negative charge (-6.50 µC) is on the left. They are 2.50 cm apart. An external electric field \( E \) with a magnitude of \( 1.85 \times 10^3 \, \text{N/C} \) is directed to the right, parallel to the wire connecting the charges.
**Note:**
For accurate calculation, consider both the electric force due to the charges and the external electric field when determining the tension in the wire.
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