A 8.00 kg block of ice, released from rest at the top of a 1.50-m-long frictionless ramp, slides downhill, reaching a speed of 2.58 m/s at the bottom. Part A What is the angle between the ramp and the horizontal? Express your answer in degrees. Submit Request Answer • Part B What would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of 10.0 N parallel to the surface of the ramp? Express your answer with appropriate units. HA ? Value Units

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A: mass of ice (m) = 2 kg distance moved (d) = 0.74 m θ = 34oinitial velocity (u) = 0 m/s

Q: the ramp an down the ra and the truc ruck starts to es the botta

A: Given as, θ =150 , m=1.5×104 kg , μ =μk From Newton's second law as, Net force =mass × acceleration…

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Q: block of ice with mass 2.00 kg slides 0.810 m down an inclined plane that slopes downward at an…

A: mass of block of ice (m) = 2 kg distance (d) = 0.810 m Angle of incline (θ) = 31o

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A: Given: mass of gymnast m = 45 kgspring constant K = 15,000 N/mcompression in spring x = 30 cm = 0.30…

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A: Given that, the value of mass and height and distance and also given coefficient of friction.

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Q: I Review I A 4500 kg spacecraft is in a circular orbit 1500 km above the surface of Mars (my = 6.42…

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Static and Kinetic Friction

Kinetic friction comes into existence when there are moving surfaces means in other words we can say that the force which comes into existing between moving surfaces is known as kinetic friction.