A 76-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.92 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.3 s, and then comes to rest.(a) What does the spring scale register before the elevator starts to move?\[ \text{N} \](b) What does the spring scale register during the first 0.92 s of the elevator's ascent?\[ \text{N} \](c) What does the spring scale register while the elevator is traveling at constant speed?\[ \text{N} \](d) What does the spring scale register during the elevator's negative acceleration?\[ \text{N} \]

Name: A 76-kg man stands on a spring scale in an elevator. Starting from re
Uploaded: 2022-11-23T13:49:28.000Z
Channel: Bartleby
Description: A 76-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.92 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1

Since you have posted a question with multiple sub-parts, we will solve the first three sub-parts for you. To get the remaining sub-part solved please repost the complete question and mention the sub-parts to be solved. Given information: Mass of the man m=76 kg. Maximum speed of the elevator v=1.2 m/s. Time taken to reach to reach maximum speed t=0.92 s.The normal force is given as, N=ma+g...1 Here, a is the acceleration of the elevator and g is the acceleration due to gravity. When the elevator is about to move, the acceleration is zero. Substituting all known values in equation (1), N=76 kg×0+9.8 m/s2=744.8 N Therefore, the spring scale reading before the elevator starts to move is 744.8 N.The acceleration is given as, a=v-ut Substituting all known values, a=1.2 m/s-00.92 s≈1.30 m/s2 Substituting all known values in equation (1), N=76 kg×1.30 m/s2+9.8 m/s2=843.6 N Therefore, the spring scale reading during the first 0.92 s is 843.6 N.When the elevator moves with the constant velocity, the acceleration is zero. Substituting all known values in equation (1), N=76 kg×0+9.8 m/s2=744.8 N Therefore, the spring scale reading before the elevator travels with constant velocity is 843.6 N.