**Required information**NOTE: *This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.*A 7-ft boom is held by a ball and socket at \( A \) and by two cables \( EBF \) and \( DC \); cable \( EBF \) passes around a frictionless pulley at \( B \). Consider the force \( P = 390 \, \text{lb} \).[Diagram Description]The diagram shows a 3D representation of a structure with the following components:- A boom \( AB \) inclined within an \( xyz \)-coordinate system. The boom is 7 feet long.- The boom starts at a ball and socket joint at point \( A \) and extends towards \( B \).- Cable \( EBF \) runs from point \( E \) at the \( y \)-axis, goes around a frictionless pulley at \( B \), and ends at point \( F \) along the \( z \)-axis.- Cable \( DC \) runs horizontally from point \( D \) on the \( z \)-axis to point \( C \) on the \( x \)-axis, positioned 4 feet from \( B \).- Distances are marked along the axes: 4 feet along \( x \), 6 feet up \( y \), and 4 feet along \( z \).- A downward force \( P = 390 \, \text{lb} \) is applied at point \( C \).**Determine the tension in each cable.**The tension in cable \( EBF \) is \_\_\_\_ lb.The tension in cable \( DC \) is \_\_\_\_ lb.

Given: The length of boom, L = 7 ft The force acting at C, P = 390 lb

Answered: A 7-ft boom is held by a ball and…

A 7-ft boom is held by a ball and socket at A and by two cables EBFand DC; cable EBFpasses around a frictionless pulley at B. Consider the force P= 390 lb. 3 ft - 3 ft→–4 ft– 4 ft

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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