A crate, weighs W= 300 lbs, is hanged using a rod CD and two springs AC and BC. The configuration shown in the figure below is under equilibrium condition. Note that the springs are stretched on this condition. You are asked to calculate the unstretched length of the springs if the spring constant kı = 2 lbs/in and k2 = 4 lbs/in. В 6 ft 60° 450 k1 W www

A crate, weighs W= 300 lbs, is hanged using a rod CD and two springs AC and BC. The configuration shown in the figure below is under equilibrium condition. Note that the springs are stretched on this condition. You are asked to calculate the unstretched length of the springs if the spring constant kı = 2 lbs/in and k2 = 4 lbs/in. В 6 ft 60° 450 k1 W www

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

A crate, weighs W= 300 lbs, is hanged using a rod CD and two springs AC and BC. The
configuration shown in the figure below is under equilibrium condition. Note that the
springs are stretched on this condition. You are asked to calculate the unstretched length of
the springs if the spring constant kı = 2 lbs/in and k2 = 4 lbs/in.
В
6 ft
60°
450
k1
W
ww

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Similar problem is already solved in bartleby. You can take reference from there. But give the answer fast.
QUESTION 1 Figure Q1 shows a space truss ABCD and a horizontal load P = 30 kN applied on it at joint D, acting in the x-direction. The rectangular coordinate system (x, y, z) is used here, all linear dimensions are given in metres, and the truss is in static equilibrium. В (0, 3, 2) D (3, 0, 0) A (0, -3, 2): P=30 kN --- X (0, 0, -3) Figure Q1: A space truss Using the method of tension coefficients, calculate: 1.1. The tension coefficientstpA , tdBānd tpc, 1.2. The magnitudes of internal forces in members DA, DB and DC, 1.3. Re-sketch the truss and show the nature of internal forces in all the members of the truss.