A 6% grade meets a -4% grade at a vertex whose directly under an overpass bridge whose underside is at elevation 152. 74 m. and carries another road across the grades at right angles. a. The length of the curve on the side of the back tangent is 70 m., while on the right side of the forward tangent is 100 m. long. Compute the vertical clearance from centreline of the bridge to the vertical curve if the elevation at PC is 142 m. b. If the underside of the bridge is level and is 10 m. wide, Find the actual clearance on the left and right edge of the bridge.

Q: 3.)  A -4% grade meets a 7% grade at station 2 + 185 of elevation 150 m. The lengths are L1 = 70 m.…

A: Downward gradient=-4% Upward gradient=7% Elevation=150 m L1=70 m, L2=50 m.

Q: The tangents of a sag curve connects at the point of intersection having Station 18+407.60 and…

A: 1. Given : At point of intersection (PI) ⇒ Station = 18 + 407.60…

Q: A 7% descending grade intersects an 9% ascending grade at the vertex, V, at station 1+ 100 having an…

A:

Q: A compound curve is laid out 480 m. from the P.C. to the P.C.C. having a radius of 763.94 m then…

A:

Q: vertical parabolic curve of length 180m has he following specifications. The point of teraction of…

A:

Q: cal parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the…

A: PVCSTATION=PVISTA-L2PVCSTATION=35300-L2PVCELV=PVIELV-g1L2PVCelv=200-0.06×L2

Q: For a portion of highway the Line AB meets BC, Point A is at a MSL of 2000 m and point B is at a MSL…

A: Given data:Elevation of A, Elevation of B, Elevation of C, =Distance between A and B is 2.5 m and…

Q: Problem No. 1: Two tangents intersect at STA 2+550. A compound curve laid on their tangents has the…

A:

Q: A +3.0 percent grade intersects a - 2.0 percent grade at station 3 + 20 and at an elevation of…

A: The expression to calculate the station of the PVC is given by, Station of PVC=Station of PVI-L2…

Q: 2. What is the elevation of the curve at sta 9 +940 if unsymmetrical parabolic curve has a forward…

A:

Q: Q7.An equal-tangent vertical curve is to be constructed between grades of -2.0% and +1.0%. The PVI…

A: Step 1

Q: A symmetrical parabolic curve has a descending grade of -0.80% which meets an ascending grade of…

A:

Q: Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a…

A: Given data, Two grade intersecting at station 1+250m g1=+6% and g2=-3% L=183m L1=121.95m and…

Q: Q 3: What is the maximum safe speed on a vertical crest

A: Given  N= +0.03(-0.03) N=0.06 Lc=200m As, S = Stopping sight distance

Q: A +4.0% grade intersects a -3.0% percent grade al r two-lane highway with a design speed of 45 mph.…

A: Given: PVI station= 222+00 Elevation= 300.00 Design speed = V=45 mph   To determine: A) the minimum…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

A: Given: The station of lower point A is 55+50. The elevation of A is 1291.2 m. The back grade is -6%.…

Q: A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed underpass…

A:

Q: A vertical curve has its highest point at a distance 48 meters from point PT. The curve is having…

A:

Q: A 669m equal tangent crest vertical curve has PVC at Sta 18+662 and at elevation 199m. The initial…

A: Given- PVCSTA=18+662E=199mn1=7.25%n2=-7.42%L=669m

Q: C Length of the first and second curve; Lc1 & Lc2 Stationing of PC Stationing of PCC Stationing of…

A:

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

A: g1 = -6% g2 = +5.8% Station at PVI = 54+00 Elevation of PVI = 1281.5m At point A - Station A - 55+50…

Q: A 850-ft equal-tangent creat vertical cuve has its PVC at station 102+00 and elevation 1000 ft. The…

A: g1 = 3.5%g2 = - 3 %Length of curve (L) = 850 ft

Q: A vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation…

A: Answer  (a) Calculation of Length of vertical curve needed to make the highest point at station 150…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

A:

Q: A horizontal curve on a two-lane highway has its PC at station 123+70 and its PI at station 130+90.…

A:

Q: curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying…

A: Given:- 5m full station curve=10 degree 7 intermediate stations  P.C.(10+300m) To find:- Compute all…

Q: (a) Station and elevation of PC & PT (b) Station of the lowest point of the curve (c) Elevation of…

A:

Q: --3% grade meets a 5% grade near an underpass. In order to maintain the minimum clearance allowed…

A: Given Data-G1=-3%G2=+5%PC=10+000elevation=228Required-To determine elevation at station 10+040

Q: Prob. 3. A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed…

A: You can determine tangent length by calculating the central angle of the curve, in degrees. An angle…

Q: A -4% grade at Sta. 5 + 700 and elev. 110.2 is to connect to a +6% grade at Sta. 6 + 100 and elev.…

A: Determine the elevation of PCC and location of PVI.

Q: A parabolic vertical curve joins a grade of -2.0% to a grade of 0.5%. The point of intersection of…

A: Soution: d = 390-300 = 90 m Eleve = 100-4 = 96 m Elevf = 0.5% of 90 = 0.45 Elevg = 2% of 90=1.8

Q: Two tangents intersect at V with back tangent having a grade of -2.75% and forward tangent of 6.25%.…

A: PI: PI means Point of Intersection. The point origin where the back and forward tangents intersect…

Q: Two tangents intersect at V with back tangent having a grade of -4% and forward tangent of 5%. A 205…

A:

Q: QI: Draw the S. F. D. and B. M. D. for the frame shown in Fig. (1)

A: Shear force and bending moment diagram

Q: A vertical equal-tangent, 100O ft long, connects an initial grade of -2.5% and a final grade of +2%.…

A:

Q: An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed…

A: Grade: G1 = 2% Grade: G2 = -1% Design speed: V = 55 mi/h Station at PVI: = 233+40 Elevation of PV:=…

Advanced Framing Techniques

In construction engineering, framing means joining together pieces of members to build a whole structure. Framing is the step where the construction project starts taking its shape. Wood, engineered wood, and structural steel are some of the framing materials used in construction. The framing technique is divided into two types, lightweight framing, and heavyweight framing. In the heavyweight framing, the vertical supports are few, and the size and weight of the pieces to be used are more like timber framing, pole building framing, and steel framing. Lightweight framing has several smaller size vertical pieces like a balloon, platform, and light-steel framing.