A 69.0-kg skier with an initial speed of 12.8 m/s coasts up a 2.30-m high rise as shown. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0760. V = ? 2.3 m 25

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Conservation Of Energy
Section: Chapter Questions
Problem 6P
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**Problem Statement:**

A 69.0-kg skier with an initial speed of 12.8 m/s coasts up a 2.30-m high rise as shown. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0760.

**Diagram Explanation:**

- The diagram shows a skier initially moving with a speed \( v_i \) of 12.8 m/s on a horizontal surface. 
- The skier then ascends a slope inclined at an angle of 25° to the horizontal, reaching a height of 2.3 meters at the top.
- The kinetic energy at the bottom is marked as \( K_i \).
- The unknown final speed at the top of the rise is labeled as \( v_f = ? \).

**Physics Concepts:**

- **Kinetic Energy (KE):** Initially, the skier has kinetic energy calculated using \( KE = \frac{1}{2} m v^2 \), where \( m \) is the mass and \( v \) is the velocity.
- **Potential Energy (PE):** As the skier ascends the slope, some kinetic energy is converted to potential energy, calculated as \( PE = mgh \), where \( h \) is the height.
- **Work Done Against Friction:** The work done by friction will also reduce the skier's kinetic energy. The frictional force can be calculated using \( f = \mu mg \cos(\theta) \), where \( \mu \) is the coefficient of friction and \( \theta \) is the slope angle. Work done by friction is \( f \cdot d \).
- **Conservation of Energy:** The mechanical energy changes due to the work done by friction and the change in potential energy as the skier moves up the slope.

This problem can be solved by applying the conservation of energy principles, taking into account the energy lost to friction as the skier ascends the slope.
Transcribed Image Text:**Problem Statement:** A 69.0-kg skier with an initial speed of 12.8 m/s coasts up a 2.30-m high rise as shown. Find her final speed at the top, given that the coefficient of friction between her skis and the snow is 0.0760. **Diagram Explanation:** - The diagram shows a skier initially moving with a speed \( v_i \) of 12.8 m/s on a horizontal surface. - The skier then ascends a slope inclined at an angle of 25° to the horizontal, reaching a height of 2.3 meters at the top. - The kinetic energy at the bottom is marked as \( K_i \). - The unknown final speed at the top of the rise is labeled as \( v_f = ? \). **Physics Concepts:** - **Kinetic Energy (KE):** Initially, the skier has kinetic energy calculated using \( KE = \frac{1}{2} m v^2 \), where \( m \) is the mass and \( v \) is the velocity. - **Potential Energy (PE):** As the skier ascends the slope, some kinetic energy is converted to potential energy, calculated as \( PE = mgh \), where \( h \) is the height. - **Work Done Against Friction:** The work done by friction will also reduce the skier's kinetic energy. The frictional force can be calculated using \( f = \mu mg \cos(\theta) \), where \( \mu \) is the coefficient of friction and \( \theta \) is the slope angle. Work done by friction is \( f \cdot d \). - **Conservation of Energy:** The mechanical energy changes due to the work done by friction and the change in potential energy as the skier moves up the slope. This problem can be solved by applying the conservation of energy principles, taking into account the energy lost to friction as the skier ascends the slope.
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