Review | Constants | Periodic TableLearning Goal:To understand the use of Hooke's law for a spring.Hooke's law states that the restoring force F on aspring when it has been stretched or compressed isproportional to the displacement a of the spring fromits equilibrium position. The equilibrium position is theposition at which the spring is neither stretched norcompressed.In Haiti, public transportation is often by taptaps, small pickup trucks with seats along the sides of the pickup bed and railings towhich passengers can hang on. Typically they carry two dozen or more passengers plus an assortment of chickens, goats,luggage, etc. Putting this much into the back of a pickup truck puts quite a large load on the truck springs.A truck has springs for each wheel, but for simplicity assume that the individual springs can be treated as one spring with a springconstant that includes the effect of all the springs. Also for simplicity, assume that all four springs compress equally when weight isadded to the truck and that the equilibrium length of the springs is the length they have when they support the load of an emptytruck.Recall that Fxã means that F is equal to aconstant times x. For a spring, the proportionalityconstant is called the spring constant and denoted byk. The spring constant is a property of the spring andmust be measured experimentally. The larger thevalue of k, the stiffer the spring.In equation form, Hooke's law can be writtenPart AA 69 kg driver gets into an empty taptap to start the day's work. The springs compress 1.7x10-2 m. What is the effective springconstant of the spring system in the taptap?Enter the spring constant numerically in newtons per meter using two significant figures.F = -ki.• View Available Hint(s)The minus sign indicates that the force is in theopposite direction to that of the spring's displacementfrom its equilibrium length and is "trying" to restore thespring to its equilibrium position. The magnitude of theforce is given by F = kx, where x is the magnitudeof the displacement.?k =N/m

Answered: A 69 kg driver gets into an empty…

A 69 kg driver gets into an empty taptap to start the day's work. The springs compress 1.7x10-2 m . What is the effective spring constant of the spring system in the taptap?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

In the reality television show "Amazing Race," a contestant is firing 12 kg watermelons from a slingshot to hit targets down the field. The slingshot is stretched from its equilibrium length by a distance of 1.8 m, and the watermelon is at ground level, 0.3 m below the launch point. The targets are at ground level 14 m horizontally away from the launch point. Calculate the spring constant of the slingshot (in N/m). (Assume the angle that the watermelon's velocity makes with the horizontal at the launch point is the same as the angle the slingshot makes with the horizontal when pulled back. Also assume the equilibrium length of the slingshot is negligible.)
2. A 10.0-kg block is released from rest at a rough 5.0 m long 30° incline. The coefficient of kinetic friction between incline and box is 0.2. At the bottom of the incline is a frictionless flat track. The block travels down the track, hits a spring of force constant k = 100 N/m. Determine (a) the speed of the block at the bottom of the incline, (b) the maximum compressing distance of the spring from its equilibrium position. (25) 30° spring
You shoot a 39.5-g pebble straight up with a catapult whose spring constant is 320.0 N/m. The catapult is initially stretched by 0.190 m. How high above the starting point does the pebble fly? Ignore air resistance
When a 3 kg mass is hung on a vertical spring, it extends the spring by 2.00 m. What is the spring constant of the spring in N/m? (Assume g = 10m/s2).
A 1.5 kg block is forced against a horizontal spring, compressing the spring 0.17 m. When released, the block moves on a horizontal table top for 1.01 m before coming to rest. The spring constant is 112 N/m. Determine the coefficient of kinetic friction between the block and the table
A 1.81-kg box rests atop a massless vertical spring with k = 3820 N/m that has been compressed by 11.4 cm from its equilibrium position. The box is released and leaves the spring when it reaches its equilibrium position. What is the maximum height the box reaches above its original position? In m
4. A 3kg block sits on a ramp, against a spring. I pull back on the block, compressing the string by 4cm, and the block moves 1.4m up the ramp, so that it is 0.5m higher than it was before, before it stops. If the force of kinetic friction on the block from the ramp is K = 7N, find the spring constant k. Ef = Ei 0.5m + 1.4m W
A 43 kg student jumps off a bridge with a 14-m-long bungee cord tied to his feet. The mass-less bungee cord has a spring constant of 399 N/m. You can assume that the bungee cord exerts no force until it begins to stretch. How far below the bridge is the student's lowest point?
9. A 7.9 kg object is suspended 10 m above the ground. Directly beneath it is a spring with a spring constant of 6500 N/m. Qualitatively describe what occurs to the energy of the system once the object is released? (Hint: Consider what occurs as the object falls, encounters the spring, and if it will go back up again!)
A 900 kg safe is 1.5 m above a heavy-duty spring when the rope holding the safe breaks. The safe hits the spring and compresses it 40 cm. What is the spring constant of the spring? Express your answer to two significant figures and include the appropriate units.