A 650 mL reaction vessel initially contains 0.0125 mol of H,S at 800 °C. Calculate partial pressure of H, at equilibrium. 2 H2S (g) = 2 H2 (g) + S2(g) Kc = 1.67x107 at 800 °C 1 atm = 760 mmHg = 760 torr = 1.013 bar R = 0.08206 L atm mol-1 K-1 = 8.314 J mol-1 K-1 31.4 mmHg 16.7 mmHg 33.3 mmHg 46.2 mmHg 62.9 mmHg
A 650 mL reaction vessel initially contains 0.0125 mol of H,S at 800 °C. Calculate partial pressure of H, at equilibrium. 2 H2S (g) = 2 H2 (g) + S2(g) Kc = 1.67x107 at 800 °C 1 atm = 760 mmHg = 760 torr = 1.013 bar R = 0.08206 L atm mol-1 K-1 = 8.314 J mol-1 K-1 31.4 mmHg 16.7 mmHg 33.3 mmHg 46.2 mmHg 62.9 mmHg
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![A 650 mL reaction vessel initially contains 0.0125 mol of H,S at 800 °C. Calculate partial pressure of H, at equilibrium.
2 H2S (g) = 2 H2 (g) + S2(g) Kc = 1.67x107 at 800 °C
1 atm = 760 mmHg = 760 torr = 1.013 bar
R = 0.08206 L atm mol-1 K-1 = 8.314 J mol-1 K-1
31.4 mmHg
16.7 mmHg
33.3 mmHg
46.2 mmHg
62.9 mmHg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F735d88bd-6956-4530-861b-fcf603fdec7d%2Fa580610d-b1c9-43fe-92e8-02e1aecfd35a%2F1hxnj5t.jpeg&w=3840&q=75)
Transcribed Image Text:A 650 mL reaction vessel initially contains 0.0125 mol of H,S at 800 °C. Calculate partial pressure of H, at equilibrium.
2 H2S (g) = 2 H2 (g) + S2(g) Kc = 1.67x107 at 800 °C
1 atm = 760 mmHg = 760 torr = 1.013 bar
R = 0.08206 L atm mol-1 K-1 = 8.314 J mol-1 K-1
31.4 mmHg
16.7 mmHg
33.3 mmHg
46.2 mmHg
62.9 mmHg
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