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A 65.9-Q resistor is connected in parallel with a 168.1-Q resistor. This parallel group is connected in series with a 30.0-0 resistor. The total combination is connected across a 16.2-V battery. Find (a) the current and (b) the power dissipated in the 168.1-0 resistor. R3 ww R₁ www V R₂ ww F

A 65.9-Q resistor is connected in parallel with a 168.1-Q resistor. This parallel group is connected in series with a 30.0-0 resistor. The total combination is connected across a 16.2-V battery. Find (a) the current and (b) the power dissipated in the 168.1-0 resistor. R3 ww R₁ www V R₂ ww F

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A 65.9-Q resistor is connected in parallel with a 168.1-0 resistor. This parallel group is connected in series with a 30.0-0 resistor. The total combination is connected across a 16.2-V battery. Find (a) the current and (b) the power dissipated in the 168.1-Q resistor. R₁ (a) Number Mi (b) Number i Units Units R3 ww V < R₂
Transcribed Image Text:A 65.9-Q resistor is connected in parallel with a 168.1-0 resistor. This parallel group is connected in series with a 30.0-0 resistor. The total combination is connected across a 16.2-V battery. Find (a) the current and (b) the power dissipated in the 168.1-Q resistor. R₁ (a) Number Mi (b) Number i Units Units R3 ww V < R₂
Expert Solution
Step 1

Given:-

The resistance is as 

R1=65.9 ΩR2= 168.1 ΩR3= 30.0 Ω

Physics homework question answer, step 1, image 1

The voltage of the battery connected to the circuit is V =16.2 V 

Find:- 

a) The current in the resistance 168.1 Ω

b) The power dissipated  in the resistance 168.1 Ω

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