A 6.5m high temporary retaining wall with 4 struts is to be constructed. Soil profile can be idealized as soft clay (CL). Natural unit weight of the soil (y) is 17kN/m². The upper strut is located 0.5m below the top of the wall and the vertical distances between struts are 1.5m. The center-to-center spacing of struts is 3.0m. A cross section view of the initial design for the wall including the struts and soil properties are shown in Figure 2. a) Calculate the forces acting on each strut. b) What is the factor of safety bottom against heave? 0.5m +1 1.5m 1.5m 1.5m 2 32 +4 1.5m Very Deep Clay C₁₂-50kPa =0° Figure 2.
A 6.5m high temporary retaining wall with 4 struts is to be constructed. Soil profile can be idealized as soft clay (CL). Natural unit weight of the soil (y) is 17kN/m². The upper strut is located 0.5m below the top of the wall and the vertical distances between struts are 1.5m. The center-to-center spacing of struts is 3.0m. A cross section view of the initial design for the wall including the struts and soil properties are shown in Figure 2. a) Calculate the forces acting on each strut. b) What is the factor of safety bottom against heave? 0.5m +1 1.5m 1.5m 1.5m 2 32 +4 1.5m Very Deep Clay C₁₂-50kPa =0° Figure 2.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A 6.5m high temporary retaining wall with 4 struts is to be constructed. Soil profile can be idealized as soft
clay (CL). Natural unit weight of the soil (y) is 17kN/m². The upper strut is located 0.5m below the top of the
wall and the vertical distances between struts are 1.5m. The center-to-center spacing of struts is 3.0m. A cross
section view of the initial design for the wall including the struts and soil properties are shown in Figure 2.
a) Calculate the forces acting on each strut.
b) What is the factor of safety bottom against heave?
0.5m
+1
1.5m
1.5m
1.5m
2
32
+4
1.5m
Very Deep Clay
C₁₂-50kPa
=0°
Figure 2.
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