A 6.510 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is µ, = 0.455 and the coefficient of kinetic friction is µ = 0.255. At time t = 0, a force F = 17.9 N is applied m µs.k horizontally to the block. State the force of friction applied to the block by the table at times t = 0 and t > 0. t = 0 17.9 N t > 0 17.9 N Consider the same situation, but this time the external force F is 36.0 N. Again, state the force of friction acting on the block at times t = 0 and t > 0. 17.9 t > 0 16.3 N t = 0 Incorrect
A 6.510 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is µ, = 0.455 and the coefficient of kinetic friction is µ = 0.255. At time t = 0, a force F = 17.9 N is applied m µs.k horizontally to the block. State the force of friction applied to the block by the table at times t = 0 and t > 0. t = 0 17.9 N t > 0 17.9 N Consider the same situation, but this time the external force F is 36.0 N. Again, state the force of friction acting on the block at times t = 0 and t > 0. 17.9 t > 0 16.3 N t = 0 Incorrect
College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Static and Kinetic Friction on a Block**
A 6.510 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is \( \mu_s = 0.455 \) and the coefficient of kinetic friction is \( \mu_k = 0.255 \). At time \( t = 0 \), a force \( F = 17.9 \, \text{N} \) is applied horizontally to the block. State the force of friction applied to the block by the table at times \( t = 0 \) and \( t > 0 \).
- \( t = 0 \) \[ 17.9 \, \text{N} \]
- \( t > 0 \) \[ 17.9 \, \text{N} \]
Consider the same situation, but this time the external force \( F \) is \( 36.0 \, \text{N} \). Again, state the force of friction acting on the block at times \( t = 0 \) and \( t > 0 \).
- \( t = 0 \) \[ \text{(Incorrect)} \, 17.9 \, \text{N} \]
- \( t > 0 \) \[ 16.3 \, \text{N} \]
**Diagram Explanation:**
The diagram shows a block of mass \( m \) on a surface, with an applied force \( F \) and friction coefficients \( \mu_s \) and \( \mu_k \) indicated. The block is subject to horizontal forces at different time intervals.
**Key Concepts:**
- **Static Friction:** The force preventing the start of motion.
- **Kinetic Friction:** The force opposing motion once started.
- **Calculations:** Use \( \mu_s \times \text{normal force} \) for static friction and \( \mu_k \times \text{normal force} \) for kinetic friction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa45c32b6-34c0-4e92-83fb-0cd14b44bbb9%2F8538b535-e29b-4e47-8b19-013b2c3b3956%2Fcj82g6j_processed.png&w=3840&q=75)
Transcribed Image Text:**Static and Kinetic Friction on a Block**
A 6.510 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is \( \mu_s = 0.455 \) and the coefficient of kinetic friction is \( \mu_k = 0.255 \). At time \( t = 0 \), a force \( F = 17.9 \, \text{N} \) is applied horizontally to the block. State the force of friction applied to the block by the table at times \( t = 0 \) and \( t > 0 \).
- \( t = 0 \) \[ 17.9 \, \text{N} \]
- \( t > 0 \) \[ 17.9 \, \text{N} \]
Consider the same situation, but this time the external force \( F \) is \( 36.0 \, \text{N} \). Again, state the force of friction acting on the block at times \( t = 0 \) and \( t > 0 \).
- \( t = 0 \) \[ \text{(Incorrect)} \, 17.9 \, \text{N} \]
- \( t > 0 \) \[ 16.3 \, \text{N} \]
**Diagram Explanation:**
The diagram shows a block of mass \( m \) on a surface, with an applied force \( F \) and friction coefficients \( \mu_s \) and \( \mu_k \) indicated. The block is subject to horizontal forces at different time intervals.
**Key Concepts:**
- **Static Friction:** The force preventing the start of motion.
- **Kinetic Friction:** The force opposing motion once started.
- **Calculations:** Use \( \mu_s \times \text{normal force} \) for static friction and \( \mu_k \times \text{normal force} \) for kinetic friction.
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