a) 5W b) 24 W Q11) The Va for the the circuit shown in Fig. 7 as seen from the terminal a-b can be found as: a)-/220 V d)-110 V e)-/165 V c)-j55 V b)-/330 V Please refer to the circuit of Fig. 8 for the following questions (Q12, Q13 and Q14). Assuming IL(0)-8 A, and V.(0)-40 V. V Q12) Neper frequency a is a) 4 rad/s b) 16 rad/s c) 25 rad/s d) 2 rad/s e) 5 rad/s Q13) Resonant frequency mo is a) 4 rad/s b) 5 rad/s c) 4 rad/s d) 16 rad/s Q14) The voltage v (t=1s) can be found as a) 10.61 V b) 14.61 V c) 16.61 V d) 8.61 V omn ma Fig.7 by the dependent source of Fig. 6 can be determined as c) 96 W d) 192 W e) 48W Q15) For the circuit shown a) 1/2 L b) 4/9 L L m m €4 L m e) 25 rad/s e) 12.61 V ESH Fig. 9 in Fig. 9, the equivalent inductance Leq is: c) 7/4 L d) 5/8 L e) 4/7 L b) R=0.20, L = 0.2 H e) R=222, L=2 H 6 mA Q19) For the circuit shown in Fig. 11, the value of C needed to make the response underdamped with unity damping factor (a = 1) is: = a) 40 mF b) 15 mF c) 26 mF d) 2.5 mF e) 7.5 mF 10 Q 8123 www Fig. 8 2mF 2102 3kQ 5KQ 4mF Fig. 10 Q16) For the circuit shown in Fig. 10, the energy stored in the 4 mF capacitor under de conditions is: a) 32 mJ b) 128 mJ c) 256 mJ d) 8 mJ e) 16 mJ Q17) If v(t)=15 cos(1000t+66°) V and i(t)=2cos(1000t+450°) A, then v(t) leads i(t) by a) 156° b)-24° c) 204° d) 24° e) 66° Q18) Assuming that the input impedance is given as Zin = 1+j1 2 and co-1 rad/s, then the input admittance can be represented as the parallel combination of: a) R=0.22, C=0.2 F c) R=10, L=1H d) R=102, C=1F 12.5 m. 0.5H C www 410 10 mF Fig. 11 The switch in Fig. 12 has been in position A for long time. At t=0, the switch moves to position B. Please refer to the circuit of Fig. 12 for the following questions (30.01 020) vots
a) 5W b) 24 W Q11) The Va for the the circuit shown in Fig. 7 as seen from the terminal a-b can be found as: a)-/220 V d)-110 V e)-/165 V c)-j55 V b)-/330 V Please refer to the circuit of Fig. 8 for the following questions (Q12, Q13 and Q14). Assuming IL(0)-8 A, and V.(0)-40 V. V Q12) Neper frequency a is a) 4 rad/s b) 16 rad/s c) 25 rad/s d) 2 rad/s e) 5 rad/s Q13) Resonant frequency mo is a) 4 rad/s b) 5 rad/s c) 4 rad/s d) 16 rad/s Q14) The voltage v (t=1s) can be found as a) 10.61 V b) 14.61 V c) 16.61 V d) 8.61 V omn ma Fig.7 by the dependent source of Fig. 6 can be determined as c) 96 W d) 192 W e) 48W Q15) For the circuit shown a) 1/2 L b) 4/9 L L m m €4 L m e) 25 rad/s e) 12.61 V ESH Fig. 9 in Fig. 9, the equivalent inductance Leq is: c) 7/4 L d) 5/8 L e) 4/7 L b) R=0.20, L = 0.2 H e) R=222, L=2 H 6 mA Q19) For the circuit shown in Fig. 11, the value of C needed to make the response underdamped with unity damping factor (a = 1) is: = a) 40 mF b) 15 mF c) 26 mF d) 2.5 mF e) 7.5 mF 10 Q 8123 www Fig. 8 2mF 2102 3kQ 5KQ 4mF Fig. 10 Q16) For the circuit shown in Fig. 10, the energy stored in the 4 mF capacitor under de conditions is: a) 32 mJ b) 128 mJ c) 256 mJ d) 8 mJ e) 16 mJ Q17) If v(t)=15 cos(1000t+66°) V and i(t)=2cos(1000t+450°) A, then v(t) leads i(t) by a) 156° b)-24° c) 204° d) 24° e) 66° Q18) Assuming that the input impedance is given as Zin = 1+j1 2 and co-1 rad/s, then the input admittance can be represented as the parallel combination of: a) R=0.22, C=0.2 F c) R=10, L=1H d) R=102, C=1F 12.5 m. 0.5H C www 410 10 mF Fig. 11 The switch in Fig. 12 has been in position A for long time. At t=0, the switch moves to position B. Please refer to the circuit of Fig. 12 for the following questions (30.01 020) vots
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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