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A 50.00-mL sample of a 0.250 M solution of butyric acid, HB, (K = 1.5 x 10 ) is titrated with 0.125 M NaOH. Complete the following tables to calculate the equilibrium [H'] and pH of the initial solution. Set up: Do not use spaces. (HB) [B'] [H'] Initial concentration 0.250 Expression for change in concentration (-x, +x, -2x, +2x, etc) ++ Expression for equilibrium concentration (see above instruction) 0.250-x Numerical answers: (HB) (B] [H'] nitial concentration, mol/L 0.250 Change in concentration, mol/L Equilibrium concentration, mol/l pH =

A 50.00-mL sample of a 0.250 M solution of butyric acid, HB, (K = 1.5 x 10 ) is titrated with 0.125 M NaOH. Complete the following tables to calculate the equilibrium [H'] and pH of the initial solution. Set up: Do not use spaces. (HB) [B'] [H'] Initial concentration 0.250 Expression for change in concentration (-x, +x, -2x, +2x, etc) ++ Expression for equilibrium concentration (see above instruction) 0.250-x Numerical answers: (HB) (B] [H'] nitial concentration, mol/L 0.250 Change in concentration, mol/L Equilibrium concentration, mol/l pH =

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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A 50.00-ml sample of a 0.250 M solution of butyric acid, HB, (K, = 1.5 x 105) is titrated with 0.125 M NaOH. %3! Complete the following tables to calculate the equilibrium [H'] and pH of the initial solution. Set up: Do not use spaces. [HB] [B'] [H*] Initial concentration 0.250 Expression for change in concentration (-x, +x, -2x, +2x, etc) -X ++ Expression for equilbrium concentration (see above instruction) 0.250-x Numerical answers: [HB] [B'] [H'] nitial concentration, mol/L 0.250 40 Change in concentration, mol/L Equilibrium concentration, mol/L pH=
Transcribed Image Text:A 50.00-ml sample of a 0.250 M solution of butyric acid, HB, (K, = 1.5 x 105) is titrated with 0.125 M NaOH. %3! Complete the following tables to calculate the equilibrium [H'] and pH of the initial solution. Set up: Do not use spaces. [HB] [B'] [H*] Initial concentration 0.250 Expression for change in concentration (-x, +x, -2x, +2x, etc) -X ++ Expression for equilbrium concentration (see above instruction) 0.250-x Numerical answers: [HB] [B'] [H'] nitial concentration, mol/L 0.250 40 Change in concentration, mol/L Equilibrium concentration, mol/L pH=
Numerical answers: [B'] [HB) [OH'] Initial concentration, mol/L Change in concentration, moL Equilibrium concentration, mol/L [H*] = mol/L pH = Calculate the number of moles of butyric present in the initial solution: mol - the volume of NaOH solution needed to reach equivalence point: mL - the total volume of the titration mixture: ml. - the initial concentration of the conjugate base of butyric acid, B", in the titrated mixture: mol/L - Ko of the conjugate base of butyric acid: - pH halfway to the equivalence point: Complete the following tables to calculate the equilibrium [H*] and pH of the titrated solution. Set up: Do not use spaces. [B'] [HB') [OH'] Initial concentration Expression for change in concentration (-x, +x, -2x, +2x, etc) Expression for equilibrium concentration (see above instruction) Numerical answers: this is a chemistry question
Transcribed Image Text:Numerical answers: [B'] [HB) [OH'] Initial concentration, mol/L Change in concentration, moL Equilibrium concentration, mol/L [H*] = mol/L pH = Calculate the number of moles of butyric present in the initial solution: mol - the volume of NaOH solution needed to reach equivalence point: mL - the total volume of the titration mixture: ml. - the initial concentration of the conjugate base of butyric acid, B", in the titrated mixture: mol/L - Ko of the conjugate base of butyric acid: - pH halfway to the equivalence point: Complete the following tables to calculate the equilibrium [H*] and pH of the titrated solution. Set up: Do not use spaces. [B'] [HB') [OH'] Initial concentration Expression for change in concentration (-x, +x, -2x, +2x, etc) Expression for equilibrium concentration (see above instruction) Numerical answers: this is a chemistry question
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