A 50.0 g piece of iron is submerged in a graduated cylinder containing 25.00 mL water, and the liquid level rises to 31.35 mL. If a 68.0 g sample of iron is added to a graduated cylinder containing 25.00 mL water, what is the final volume reading? d = v O 33.46 mL O 15.32 mL O 6.35 mL O 8.64 mL O 25.00 mL
A 50.0 g piece of iron is submerged in a graduated cylinder containing 25.00 mL water, and the liquid level rises to 31.35 mL. If a 68.0 g sample of iron is added to a graduated cylinder containing 25.00 mL water, what is the final volume reading? d = v O 33.46 mL O 15.32 mL O 6.35 mL O 8.64 mL O 25.00 mL
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Educational Resource: Calculating Volume Displacement
**Problem Statement:**
A 50.0 g piece of iron is submerged in a graduated cylinder containing 25.00 mL of water, and the liquid level rises to 31.35 mL.
If a 68.0 g sample of iron is added to a graduated cylinder containing 25.00 mL of water, what is the final volume reading?
**Formula:**
\[
d = \frac{m}{V}
\]
**Choices:**
- 33.46 mL
- 15.32 mL
- 6.35 mL
- 8.64 mL
- 25.00 mL
### Explanation:
The problem involves determining the volume displacement caused by submerging a piece of metal in water. The initial experiment, with a 50.0 g piece of iron, resulted in a rise from 25.00 mL to 31.35 mL, indicating the volume of the iron.
For the second part, given the mass of 68.0 g, use the concept of density to calculate the volume of water displaced, and then determine the new volume level in the graduated cylinder.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdfb365ff-2e06-4733-a8e2-bdf1a834f6e8%2Fe5342016-dc2f-4bfd-ab34-ff6a2645b8a6%2F3npqrp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Educational Resource: Calculating Volume Displacement
**Problem Statement:**
A 50.0 g piece of iron is submerged in a graduated cylinder containing 25.00 mL of water, and the liquid level rises to 31.35 mL.
If a 68.0 g sample of iron is added to a graduated cylinder containing 25.00 mL of water, what is the final volume reading?
**Formula:**
\[
d = \frac{m}{V}
\]
**Choices:**
- 33.46 mL
- 15.32 mL
- 6.35 mL
- 8.64 mL
- 25.00 mL
### Explanation:
The problem involves determining the volume displacement caused by submerging a piece of metal in water. The initial experiment, with a 50.0 g piece of iron, resulted in a rise from 25.00 mL to 31.35 mL, indicating the volume of the iron.
For the second part, given the mass of 68.0 g, use the concept of density to calculate the volume of water displaced, and then determine the new volume level in the graduated cylinder.
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