Page 4 of 4Torque And Static Equilibrium4. A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall.If the ladder is in a state of impending motion when it makes an angle of 65° withrespect to the floor, calculate the force exerted by the wall onto the ladder.Solution and Answer:Since the ladder is uniform, then the center of gravity ofthe ladder is at its geometric center. We use the first andsecond conditions for equilibrium in order to tackle thisproblem. The chosen axis of rotation is at the pointwhere the ladder makes contact with the ground. LetFwall and f be the forces due to the wall and due tofriction, respectively. From the first conditions ofequilibrium, we get:force exerted by wallweigheermal forcection=f+(-Fwatt) = 0B = n + (-W) = 0The second condition for equilibrium is: Twall + (-Triction) + Tn + (-Tweight) = 0The frictional force and the normal force are located at the pivot point. Thisfurther simplifies to:Twall + (-Tweight) = 0(Fwatl)(5 m)(sin65°) = (W)(2.5 m)(sin25°)Now, compute for the value of the force exerted by the wall on the ladder, Fwall-Hint: Compute for weight, W = mladder9 first before evaluating the value for Fwall-

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A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall. If the ladder is in a state of impending motion when it makes an angle of 65° with respect to the floor, calculate the force exerted by the wall onto the ladder.

A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall. If the ladder is in a state of impending motion when it makes an angle of 65° with respect to the floor, calculate the force exerted by the wall onto the ladder.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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