Page 4 of 4Torque And Static Equilibrium4. A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall.If the ladder is in a state of impending motion when it makes an angle of 65° withrespect to the floor, calculate the force exerted by the wall onto the ladder.Solution and Answer:Since the ladder is uniform, then the center of gravity ofthe ladder is at its geometric center. We use the first andsecond conditions for equilibrium in order to tackle thisproblem. The chosen axis of rotation is at the pointwhere the ladder makes contact with the ground. LetFwall and f be the forces due to the wall and due tofriction, respectively. From the first conditions ofequilibrium, we get:force exerted by wallweigheermal forcection=f+(-Fwatt) = 0B = n + (-W) = 0The second condition for equilibrium is: Twall + (-Triction) + Tn + (-Tweight) = 0The frictional force and the normal force are located at the pivot point. Thisfurther simplifies to:Twall + (-Tweight) = 0(Fwatl)(5 m)(sin65°) = (W)(2.5 m)(sin25°)Now, compute for the value of the force exerted by the wall on the ladder, Fwall-Hint: Compute for weight, W = mladder9 first before evaluating the value for Fwall-

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A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall. If the ladder is in a state of impending motion when it makes an angle of 65° with respect to the floor, calculate the force exerted by the wall onto the ladder.

A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall. If the ladder is in a state of impending motion when it makes an angle of 65° with respect to the floor, calculate the force exerted by the wall onto the ladder.

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Rotational Equilibrium And Rotational Dynamics

In physics, the state of balance between the forces and the dynamics of motion is called the equilibrium state. The balance between various forces acting on a system in a rotational motion is called rotational equilibrium or rotational dynamics.

Equilibrium of Forces

The tension created on one body during push or pull is known as force.

Question

Page 4 of 4
Torque And Static Equilibrium
4. A 5-m uniform ladder of mass 15 kg is held stationary against a frictionless wall.
If the ladder is in a state of impending motion when it makes an angle of 65° with
respect to the floor, calculate the force exerted by the wall onto the ladder.
Solution and Answer:
Since the ladder is uniform, then the center of gravity of
the ladder is at its geometric center. We use the first and
second conditions for equilibrium in order to tackle this
problem. The chosen axis of rotation is at the point
where the ladder makes contact with the ground. Let
Fwall and f be the forces due to the wall and due to
friction, respectively. From the first conditions of
equilibrium, we get:
force exerted by wall
weighe
ermal force
ction
=f+(-Fwatt) = 0
B = n + (-W) = 0
The second condition for equilibrium is: Twall + (-Triction) + Tn + (-Tweight) = 0
The frictional force and the normal force are located at the pivot point. This
further simplifies to:
Twall + (-Tweight) = 0
(Fwatl)(5 m)(sin65°) = (W)(2.5 m)(sin25°)
Now, compute for the value of the force exerted by the wall on the ladder, Fwall-
Hint: Compute for weight, W = mladder9 first before evaluating the value for Fwall-

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