A 47 g tennis ball is served at 45 m/s. If the ball started from rest, what impulse was applied to the ball by the racket? 8.5 N*s 4.3 N*s 3.2 N*s 2.1 N*s O 2.6 N*s

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Chapter1: Units, Trigonometry. And Vectors
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**Question:**

A 47 g tennis ball is served at 45 m/s. If the ball started from rest, what impulse was applied to the ball by the racket?

**Options:**

- ○ 8.5 N·s
- ○ 4.3 N·s
- ○ 3.2 N·s
- ○ 2.1 N·s
- ○ 2.6 N·s

**Explanation:**

Impulse is the change in momentum of an object when a force is applied over time. It can be calculated using the formula:

\[ \text{Impulse} = \Delta p = m \times \Delta v \]

where \( \Delta p \) is the change in momentum, \( m \) is the mass, and \( \Delta v \) is the change in velocity.

In this example, the mass \( m \) of the tennis ball is 47 g or 0.047 kg, and the change in velocity \( \Delta v \) is 45 m/s \((45 \, \text{m/s} - 0 \, \text{m/s})\).

Calculating impulse:

\[ \text{Impulse} = 0.047 \, \text{kg} \times 45 \, \text{m/s} = 2.115 \, \text{N·s} \]

Therefore, the correct answer is approximately:

- ○ 2.1 N·s
Transcribed Image Text:**Question:** A 47 g tennis ball is served at 45 m/s. If the ball started from rest, what impulse was applied to the ball by the racket? **Options:** - ○ 8.5 N·s - ○ 4.3 N·s - ○ 3.2 N·s - ○ 2.1 N·s - ○ 2.6 N·s **Explanation:** Impulse is the change in momentum of an object when a force is applied over time. It can be calculated using the formula: \[ \text{Impulse} = \Delta p = m \times \Delta v \] where \( \Delta p \) is the change in momentum, \( m \) is the mass, and \( \Delta v \) is the change in velocity. In this example, the mass \( m \) of the tennis ball is 47 g or 0.047 kg, and the change in velocity \( \Delta v \) is 45 m/s \((45 \, \text{m/s} - 0 \, \text{m/s})\). Calculating impulse: \[ \text{Impulse} = 0.047 \, \text{kg} \times 45 \, \text{m/s} = 2.115 \, \text{N·s} \] Therefore, the correct answer is approximately: - ○ 2.1 N·s
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