A 460-V. 25-hp. 60 Hz. four-pole. Y-connected induction motor has thefollowing impedances in ohms per phase referred to the stator circuit:RI = 0.641 ohmX1 = 1.106 ohmR2 = 0.332 ohmX2 = 0.464 ohm XM= 26.3 ohm(a) What is the maximum torque of this motor?(b) At what speed and slip does it occur?(c) What is the starting torque of this motor?(d) When the rotor resistance is doubled. what is the speed at which the

The per-phase equivalent circuit parameters referred to the stator of a 4-pole, 25 hp, 460 V, 60 Hz,…

Answered: A 460-V. 25-hp. 60 Hz. four-pole.…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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A) Although the magnetic field for each phase of a 3-phase induction motor is merely switching back and forth between north and south poles, the resultant magnetic influence from all phases sets up a rotating magnetic field to cut the rotor conductors. a) true b) false B) In a two-pole stator winding of a 3-phase motor, how many revolutions does the rotating tr) magnetic field make in one cycle of the electrical current? a) one b) 60 c) 3600 d) none of the above
A 460-V, 25-hp, 60-Hz, four pole, Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit: R₁ = 0.641Ω R₂ = 0.3320 X₁ = 1.106Ω X₂ = 0.464Ω RM = 26.3Ω The total rotational losses are 1100 W and are assumed to be constant. The core loss is lumped in with the rotational losses. For a rotor slip of 2.2 % at the rated voltage and rated frequency, find the motor's a) Speed d) Pconv and Pout b) Stator current e) Tind and Tload c) Power factor f) Efficiency Activate
The rotor of a 3-phase, 60-Hz, 4-pole induction motor gets a total of 120kW through the air gap with a rotor frequency of 3Hz. a. What is the rotor speed (RPM)? b. What is the rotor copper loss (W)?
A 3-phase, 50-Hz induction motor with its rotor star-connected gives 500-V(r.m.s.) at standstill between the slip-rings on open-circuit. Calculate the current and power factor at standstill when the rotor winding is joined to a star-connected external circuit, each phase of which has a resistance of 10 Q and an inductance of 0.04 H. The resistance per phase of the winding is 0.2 Q and its inductance is 0.04 H. Also, calculate the current and power factor when the slip-rings are short-circuited and the motor is running with a slip of 5 per cent. Assume flux remain constant.
In a three-phase induction motor the maximum torque occurs at 20% slip and the equivalent resistance of the secondary is 0.04Ω per phase. Find the equivalent load resistance and the load voltage and the load current. Output power is 20 kW.
A large 3-phase, 4160 V, 60 Hz, squirrel-cage induction motor draws a current of 400 A and the total active power of 2500 kW when operating at full-load. The corresponding speed is accurately measured and is found to be 1178 r/min. The stator is connected in wye and the resistance between two stator terminals is 0.15 0. The total iron losses are 26.5 kW and the windage and friction losses are 15 kW. Calculate the following: The power factor at full-load The active power supplied to the rotor The total I²R losses in the rotor The load mechanical power [kW], torque [kN.m], and efficiency [%] a. b. C. d.
A 400V, 25hp, 60HZ, 4 pole, Y-connected induction motor has the following impedances in ohms per phase referred to the stator circuit: R1=0.6410, X1=1.106 Q, Rp=11.080, Xf=6.680 .The total rotational (windage and friction) losses are 1100 W and are assumed to be constant. The core loss is jumped in with the rotational losses. For a rotor slip of 3.2% at the rated voltage and rated frequency, the stator current is
The use of a series capacitor with the auxiliary windings of a single-phase induction motor permits: * The obtaintion a 90-degrees phase angle between currents in the main and auxiliary windings. The garantee a relatively high starting torque all above
(Qld) A three-phase 20-pole induction motor is rated at 800 V, 50 Hz. What is the synchronous speed of this machine if the voltage at its terminals is reduced to 400 V (a) 150 rpm, (b) 300 rpm, (c) 600 rpm, (d) 3000 rpm
A three-phase, two-pole, 35 hp, 480 V, 60 Hz, Y-connected induction motor has the following constants in ohms per phase referred to the stator: R = 0.322N R2 = 0.196 Q X1 = 0.6752 X2 = 0.510Q Xm = 12.52 The total rotational losses are 1850 W and are assumed to be constant. The core loss is lumped in with the rotational losses. For a rotor slip of 3% at the rated voltage and rated frequency, determine the following: (a) The speed in rpm and in rad/s power factor (d) The developed power and output power (e) The developed torque and output torque (f) The efficiency. (b) The stator current (c) The
In a 3-phase, 4-pole induction motor, The power crossing the air gap of a 60 Hz is 42.6 kW, and the power converted from electrical to mechanical form in the motor is 39.6 kW. If the total mechanical losses are 1000 W, find the load torque of this motor? Select one: O a. None O b. Tload = 208.4 N.m. O c. Tjoad = 232.6 N.m. O d. Tjoad = 220.3 N.m. Clear my choice
The rotor of a 3-phase, 60 Hz, 4-pole induction motor takes 118 kW at 3Hz. The motor has stator copped loss of 2.95 kW, a mechanical loss of 2kW and a stator core loss of 1.7 kW. Solve for the motor efficiency

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