A 460 mm x 510 mm rectangular concrete interior column is reinforced with ten - 19-mm-diameter bars. The column rest centrally on a 2 m x 3 m x 710 mm rectangular spread footing as shown in Figure 1. The design properties used are, for column: f’c = 21 MPa, fy = 276 MPa; for footing: f’c = 35 MPa, fy = 345 MPa, ys = 20.425 kN/m3, yc = 23.5 kN/m3, 75 mm clear cover, 25-mm- diameter and allowable soil pressure of 200 kPa. find the following: 1. What is the value of the column capacity Pu in kN? 2. What is the effective depth of footing as required by one-way shear or beam shear in the short direction in mm? 3. What is the effective depth of footing as required by one-way shear or beam shear in the long direction in mm?
A 460 mm x 510 mm rectangular concrete interior column is reinforced with ten - 19-mm-diameter
bars. The column rest centrally on a 2 m x 3 m x 710 mm rectangular spread footing as shown in
Figure 1. The design properties used are, for column: f’c = 21 MPa, fy = 276 MPa; for footing:
f’c = 35 MPa, fy = 345 MPa, ys = 20.425 kN/m3, yc = 23.5 kN/m3, 75 mm clear cover, 25-mm-
diameter and allowable soil pressure of 200 kPa.
find the following:
1. What is the value of the column capacity Pu in kN?
2. What is the effective depth of footing as required by one-way shear or beam shear in the
short direction in mm?
3. What is the effective depth of footing as required by one-way shear or beam shear in the
long direction in mm?
4. What is the governing effective depth of footing as required by two-way shear or punching
shear mm?
5. How many rebars are needed in the long direction of the footing as required by bending
moment based on the given “average effective depth”. Round off your answer to whole
number?
6. How many rebars are needed in the short direction of the footing as required by bending
moment based on the given “average effective depth”. Round off your answer to whole
number?
7. How many pieces of bars are distributed in the inner band and each of the outer band?
Use an average effective depth “d” of 610 mm.
![Note: The equation of column capacity for tied column is:
Pu= (0.80) Ag [0.85 f'c (1-pg) + Pg fy]
where $ = 0.65
Figure 1
Pu
510 mm
3m
460 mm
1.25m
710 mm
2m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5003cfa8-1ade-45ee-a585-97a724e18632%2Fc61d87b0-97b5-49a2-8275-2621f571bbe2%2F93q1fys_processed.png&w=3840&q=75)
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