Problem 5.6A 450 diameter concrete spiral column is to be designed to support a factored axial load of 3200 kN.Clear bar covering is 40 mm and the aggregate size is 25 mm. Use the 2010 NSCP with fc = 28 MPa, fy = 415MPa, fyt = 415 MPa. Limit the gross steel percentage to 2%. Find the followinga)b)c)The mumber of pcs of 28 mm diameter bars for the longitudinal reinforcements.The spacing of the 10 mm diameter spiral reinforcements in mm.Which of the following mostly nearly gives the clear spacing of the main longitudinal reinforcements inmm A 450 mm square tied RC column is to cary axial service loads of 1500 kN dead load and 800 kN liveload. Assume column to be short columm and any moment caused by the loads can be neglected Use 2010NSCP, iffc=28 MPa and fy=415 MPa, determine:a)b)The factored axial load.The required number of 28 mm diameter longitudinal bars.c)The maximum allowable spacing of 10 mm điameter lateral bars.

Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

A 450 mm square tied RC column is to carry axial service loads of 1500 kN dead load and 800 kN live load. Assume column to be short column and any moment caused by the loads can be neglected Use 2010 NSCP, iffc= 28 MPa and fy = 415 MPa, determine: The factored axial load. b) The required mumber of 28 mm diameter longitudinal bars. c) The maximum allowable spacing of 10 mm diameter lateral bars.

A 450 mm square tied RC column is to carry axial service loads of 1500 kN dead load and 800 kN live load. Assume column to be short column and any moment caused by the loads can be neglected Use 2010 NSCP, iffc= 28 MPa and fy = 415 MPa, determine: The factored axial load. b) The required mumber of 28 mm diameter longitudinal bars. c) The maximum allowable spacing of 10 mm diameter lateral bars.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

'bd . As per IS 456:2000 for M20 grade concrete and plain barsin tension the design bond stress t= 1.2 MPa Further, IS 456:2000 permits this design bond stress value to be increased by 60% for HSD bars. The stress in the HSDreinforcing steel barsin tension, a MPa. Find the required development length, La for HSD barsin terms of the bar diameter, = 360 S o.
A symmetrical cross-section of a reinforced concrete shown has a value of f'c = 26.27 MPa and fy = 414 MPa. Calculate the nominal capacity based on the maximum steel area for a tension- controlled condition. Use the following dimensions: b = 498 mm d = 709 mm t = 152 mm web thickness - 152 mm b 1 I d
If the compressive strength of the concrete is 4 ksi and the yield strength of steel is 60 ksi, the value of that should be used in computing the design moment strength oMn for the beam section should be 23.5 in 1.5424 0.65 0.48 0.9 3#9 14 in 26 in
The grade of the concrete is M25. Find the values of design strength in- 1. Direct Compression. 2. Bending Compression & 3. Flexural Tension.
2. Tensile strength of concrete is about: (20-35)% of compressive strength (45-70)% of compressive strength None of the above. Tension controlled section Balanced section Compression-controlled section 4- The reduction factor (0) is equal to 0.9 if the: Es 2 Ety + 0.003 Es S Ety + 0.003 Es Ety 5- The design method which use the factored loads is - Working stress method - Ultimate design Method - None of above 6- If p< Po therefore the section is - Under reinforced - Over reinforced - None of above
A rectangular beam has the following properties. Assume 12 mm stirrups. Assume a single layer of reinforcements. Calculate Mu. Given: Width of the beam, = 300 mm Over-all depth, h = 425 mm Tension reinforcements = 5 pcs 28 mm dia Comp reinforcements = 4 pcs 20 mm dia Specified strength of concrete, f'c = 28 Мра Steel yield strength, fy = 345 MPа Note: Round off your final answer in 3 decimal places. No need to type the units.
For the bean shown below, the concrete strength is 5000 psi and the yield strength is 60,000 psi. For the midspan section shown, check if steel yields and compute ØM, and compare it with M. WD = 1.2 kips/ft plus weight of beam WL = 1.5 kips/ft %3D 20.5 in 23 in 3 no. 9 bars 18 ft 11 in.
Determine the development length required in bar diameter for the epoxy-coated bottom bars of the beam with 4 - 25mmΦ longitudinal bars annd 10mm stirrups @ 200mm o.c., bw = 400mm, side and bottom cover = 80mm, spacing between bars is 80mm o.c., normal concrete with f'c = 21 MPa, fy = 420 MPa. Consider Ktr in calculation. Express your answer in whole number.
What is the shear force to be carried by the reinforcements of a beam subjected to axial tension if it has a width of 313 mm and an over-all depth of 477 mm? The specified compressive lightweight concrete is 22.2 MPa and the yield strength of stirrups is 333 MPa. The distance of tension reinforcements from the outer fiber of the beam is 59 mm. Round off your final answer in 3 decimal places. Loadings: VDL = 72 kN %3D VLL = 62 kN Axial Tension (DL) = 90 kN Axial Tension (LL) = 19 kN
The flexural tensile strength of M25 grade of concrete, in N/mm², as per IS:456-2000 is A 0.5 B 5 C 2.25 D 3.5
Referenced concrete When designing the same bim Why is the load in the case of moment greater than the load in the case of shear?
The loadsshown on the beam with a cross section at midspan as shown, are service (unfactored)loads. The concrete used is a normal weight concrete with compressive strength of 4000 psi.The yield strength of the reinforcement is 60,000psi. For the midspan section shown, computeφMn and show that it exceeds Mu