**Physics Problem: Calculating Average Force****Problem Statement:**A 40.4-kg skater is standing at rest in front of a wall. By pushing against the wall, she propels herself backward with a velocity of -1.80 m/s. Her hands are in contact with the wall for 0.945 s. Ignore friction and wind resistance. Find the average force she exerts on the wall (which has the same magnitude, but opposite direction, as the force that the wall applies to her). Note that this force has direction, which you should indicate with the sign of your answer.**Input Fields:**- **Number:** [Input box]- **Units:** [Dropdown menu]**Explanation:**To solve this problem, we need to calculate the average force using the change in momentum and the time during which the force acts. This relies on the concept of impulse in physics, which is given by the equation:\[ \text{Impulse} = \Delta p = F_{\text{average}} \cdot \Delta t \]Where:- \(\Delta p\) = Change in momentum- \(F_{\text{average}}\) = Average force- \(\Delta t\) = Time duration**Step-by-Step Calculation:**1. **Determine the skater's initial and final momentum:** - Initial velocity (\(v_i\)) = 0 (since the skater is at rest) - Final velocity (\(v_f\)) = -1.80 m/s (as given) - Mass (\(m\)) = 40.4 kg (as given) \[ \Delta v = v_f - v_i = -1.80 \, \text{m/s} - 0 = -1.80 \, \text{m/s} \]2. **Calculate the change in momentum (\(\Delta p\)):** \[ \Delta p = m \cdot \Delta v = 40.4 \, \text{kg} \times (-1.80 \, \text{m/s}) = -72.72 \, \text{kg} \cdot \text{m/s} \]3. **Calculate the average force (\(F_{\text{average}}\)):** \[ F_{\text{average}} = \frac{\Delta p}{\Delta t} =

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A 40.4-kg skater is standing at rest in front of a wall. By pushing against the wall she propels herself backward with a velocity of -1.80 m/s. Her hands are in contact with the wall for 0.945 s. Ignore friction and wind resistance. Find the average force she exerts on the wall (which has the same magnitude, but opposite direction, as the force that the wall applies to her). Note that this force has direction, which you should indicate with the sign of your answer. Number i Units

A 40.4-kg skater is standing at rest in front of a wall. By pushing against the wall she propels herself backward with a velocity of -1.80 m/s. Her hands are in contact with the wall for 0.945 s. Ignore friction and wind resistance. Find the average force she exerts on the wall (which has the same magnitude, but opposite direction, as the force that the wall applies to her). Note that this force has direction, which you should indicate with the sign of your answer. Number i Units

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”

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**Physics Problem: Calculating Average Force**

**Problem Statement:**
A 40.4-kg skater is standing at rest in front of a wall. By pushing against the wall, she propels herself backward with a velocity of -1.80 m/s. Her hands are in contact with the wall for 0.945 s. Ignore friction and wind resistance. Find the average force she exerts on the wall (which has the same magnitude, but opposite direction, as the force that the wall applies to her). Note that this force has direction, which you should indicate with the sign of your answer.

**Input Fields:**
- **Number:** [Input box]
- **Units:** [Dropdown menu]

**Explanation:**

To solve this problem, we need to calculate the average force using the change in momentum and the time during which the force acts. This relies on the concept of impulse in physics, which is given by the equation:

\[ \text{Impulse} = \Delta p = F_{\text{average}} \cdot \Delta t \]

Where:
- \(\Delta p\) = Change in momentum
- \(F_{\text{average}}\) = Average force
- \(\Delta t\) = Time duration

**Step-by-Step Calculation:**

1. **Determine the skater's initial and final momentum:**
- Initial velocity (\(v_i\)) = 0 (since the skater is at rest)
- Final velocity (\(v_f\)) = -1.80 m/s (as given)
- Mass (\(m\)) = 40.4 kg (as given)

\[ \Delta v = v_f - v_i = -1.80 \, \text{m/s} - 0 = -1.80 \, \text{m/s} \]

2. **Calculate the change in momentum (\(\Delta p\)):**

\[ \Delta p = m \cdot \Delta v = 40.4 \, \text{kg} \times (-1.80 \, \text{m/s}) = -72.72 \, \text{kg} \cdot \text{m/s} \]

3. **Calculate the average force (\(F_{\text{average}}\)):**

\[ F_{\text{average}} = \frac{\Delta p}{\Delta t} =

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