A frog with some sort of little monster on his back is swimming in a bathtub of split tomato soup. The frog's mass is m1 = 0.0280 kg, and the monster's mass is m2 = 0.0300 kg. The frog propels the monster and himself forward with a constant force of F = 0.440 N and accelerates at a constant rate of a = 2.65 m/s^2.  a) What is the resistive force of the split tomato soup on the frog? b) If the frog starts at rest at one side of the bathtub and swims across its length in t = 1.91 s, how long is the bathtub? c) How much work is done by the split tomato soup on the frog?

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A frog with some sort of little monster on his back is swimming in a bathtub of split tomato soup. The frog's mass is m1 = 0.0280 kg, and the monster's mass is m2 = 0.0300 kg. The frog propels the monster and himself forward with a constant force of F = 0.440 N and accelerates at a constant rate of a = 2.65 m/s^2. 

a) What is the resistive force of the split tomato soup on the frog?

b) If the frog starts at rest at one side of the bathtub and swims across its length in t = 1.91 s, how long is the bathtub?

c) How much work is done by the split tomato soup on the frog?

 

Expert Solution
Step 1

Given,

The mass of the frog m1=0.0280 kg

The mass of the monster: m2 = 0.0300 kg

The force applied by the frog: F = 0.440 N

Acceleration of the frog: a = 2.65 m/s2

The initial speed of the frog: u =0

It swims across its length in t = 1.91 s

Now, The effective force required to achieve the acceleration is given by:

Feff=(m1+m2)×a=(0.0280+0.0300)×2.65=0.1537 N 

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