A 4.912-g sample of a petroleum product was burned in a tube furnace, and the SO 2 produced was collected in 3 % H 2 0 2. Reaction: SO 2 (g) + H 20 2 → H 2 SO 4 A 25.00-mL portion of 0.00873M NAOH was introduced into the solution of H 2 SO 4 , following which the excess base was back-titrated with 15.17 mL of 0.01102 M HCl. Calculate the sulfur concentration in the sample in parts per million.
A 4.912-g sample of a petroleum product was burned in a tube furnace, and the SO 2 produced was collected in 3 % H 2 0 2. Reaction: SO 2 (g) + H 20 2 → H 2 SO 4 A 25.00-mL portion of 0.00873M NAOH was introduced into the solution of H 2 SO 4 , following which the excess base was back-titrated with 15.17 mL of 0.01102 M HCl. Calculate the sulfur concentration in the sample in parts per million.
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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
Transcribed Image Text:A 4.912-g sample of a petroleum product was burned in a tube
furnace, and the SO 2 produced was collected in 3 % H 2 0 2.
Reaction:
SO 2 ( g) + H 20 2 → H 2 SO 4
A 25.00-mL portion of 0.00873 M NaOH was introduced into the
solution of H 2 SO 4, following which the excess base was
back-titrated with 15.17 mL of 0.01102 M HCl. Calculate the sulfur
concentration in the sample in parts per million.
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