A 4.81 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee cup calorimeter. Before placing the sample in the water, the temperature of the salt and water is 23.72°C. After the salt has completely dissolved, the temperature of the solution is 28.54°C. a.Given that 154.81 g of solution increased in temperature by 4.82 °C, how much heat, in J, was gained by the solution? Assume the specific heat of the solution is the same as water, 4.184 J/g・°C. b.What is the heat for dissolution reaction of 4.81g of salt? c.How many moles of unknown salt were used in reaction? d.What is the enthalpy change (in kJ/mol of salt) for dissolution reaction?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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A 4.81 g sample of an unknown salt (MM = 116.82 g/mol) is dissolved in 150.00 g water in a coffee cup calorimeter. Before placing the sample in the water, the temperature of the salt and water is 23.72°C. After the salt has completely dissolved, the temperature of the solution is 28.54°C.

a.Given that 154.81 g of solution increased in temperature by 4.82 °C, how much heat, in J, was gained by the solution? Assume the specific heat of the solution is the same as water, 4.184 J/g・°C.

b.What is the heat for dissolution reaction of 4.81g of salt?

c.How many moles of unknown salt were used in reaction?

d.What is the enthalpy change (in kJ/mol of salt) for dissolution reaction? 

Expert Solution
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Specific heat: It is defined as the amount of heat required to raise the temperature of the substance of 1kg by 1-degree celsius. It is represented by symbol c. It is represented as

q=mc∆T

Heat of dissolution: It is also known as the heat of solution and it is associated with the dissolution of a substance in a solvent at constant pressure resulting in infinite solution.

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