A 4.5-kg object is dropped vertically (with zero horizontal speed) from a tallbuilding with an initial velocity 6.6 m/s (positive is downwards). Due toaerodynamic drag, the object's downward acceleration is given by a = g -(k/m)*v2where g is acceleration due to gravity (use 9.81 m/s?) and k = 0.19 kg/m is acoefficient related to aerodynamic drag. Determine the distance the object will fallto reach 90% of its terminal velocity. Assume the building is tall enough so that theobject can reach that speed and that g is constant.Hints:• First, calculate the object's terminal velocity. This occurs when the accelerationof the object is zero.•Szdx = In|æ| + c and S= In|f(x)| +c%3DJ(2)Give your answer in metres and round the final answer to two decimal places.

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