A 4.20-kg object is attached to a vertical rod by two strings as shown in the figure below. The object rotates in a horizontal circle at constant speed 5.95 m/s. 2.00 m (3,00 m 2.00 m (a) Find the tension in the upper string. (b) Find the tension in the lower string. N Need Help? Read It

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Chapter1: Units, Trigonometry. And Vectors
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A 4.20-kg object is attached to a vertical rod by two strings as shown in the figure below. The object rotates in a horizontal circle at constant speed 5.95 m/s.

**Diagram Explanation:**
- There is a vertical rod with two strings attached to a blue object (mass \( m \)).
- The strings are at an angle, forming a conical pendulum.
- The upper string is 2.00 m long, and the lower string is also 2.00 m long.
- The vertical separation between the rod's attachment points for the strings is 3.00 m.

**Problem:**
(a) Find the tension in the upper string.
\[ \text{Tension} =  \text{N} \]

(b) Find the tension in the lower string.
\[ \text{Tension} = \text{N} \]

**Need Help?**
[Read It]
Transcribed Image Text:A 4.20-kg object is attached to a vertical rod by two strings as shown in the figure below. The object rotates in a horizontal circle at constant speed 5.95 m/s. **Diagram Explanation:** - There is a vertical rod with two strings attached to a blue object (mass \( m \)). - The strings are at an angle, forming a conical pendulum. - The upper string is 2.00 m long, and the lower string is also 2.00 m long. - The vertical separation between the rod's attachment points for the strings is 3.00 m. **Problem:** (a) Find the tension in the upper string. \[ \text{Tension} = \text{N} \] (b) Find the tension in the lower string. \[ \text{Tension} = \text{N} \] **Need Help?** [Read It]
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