Q7 **Physics Problem: Circular Motion**A 23 kg mass is connected to a nail on a frictionless table by a (massless) string of length 1.3 m. If the tension in the string is 51 N while the mass moves in a uniform circle on the table, how long does it take for the mass to make one complete revolution?- ○ 5.2 s- ○ 4.8 s- ○ 4.5 s- ○ 3.8 s**Explanation:**For uniform circular motion, the centripetal force required to keep an object moving in a circle is provided by the tension in the string. The centripetal force \( F_c \) is given by the formula:\[ F_c = \frac{m v^2}{r} \]Where:- \( m \) is the mass of the object (23 kg)- \( v \) is the tangential velocity- \( r \) is the radius of the circle (1.3 m)Here, \( F_c = 51 \, \text{N} \). You can solve for \( v \) and then use it to find the period \( T \) of the revolution:\[ v = \sqrt{\frac{F_c \cdot r}{m}} \]The period \( T \) is the time it takes to make one complete revolution and is given by:\[ T = \frac{2 \pi r}{v} \]Use these formulas to calculate how long it takes for the mass to make one complete revolution.

Name: Q7 **Physics Problem: Circular Motion**A 23 kg mass is connected to a
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Description: Q7 **Physics Problem: Circular Motion**A 23 kg mass is connected to a nail on a frictionless table by a (massless) string of length 1.3 m. If the tension in the string is 51 N while the mass moves in a uniform circle on the table, how long does it ta

mass (m) = 23 kg Length of string (r) = 1.3 m Tension (T) = 51 N

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A 23 kg mass is connected to a nail on a frictionless table by a (massless) string of length 1.3 m. If the tension in the string is 51 N while the mass moves in a uniform circle on the table, how long does it take for the mass to make one complete revolution? 5.2 s 4.8 s 4.5 s 3.8 s

A 23 kg mass is connected to a nail on a frictionless table by a (massless) string of length 1.3 m. If the tension in the string is 51 N while the mass moves in a uniform circle on the table, how long does it take for the mass to make one complete revolution? 5.2 s 4.8 s 4.5 s 3.8 s

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**Physics Problem: Circular Motion**

A 23 kg mass is connected to a nail on a frictionless table by a (massless) string of length 1.3 m. If the tension in the string is 51 N while the mass moves in a uniform circle on the table, how long does it take for the mass to make one complete revolution?

- ○ 5.2 s
- ○ 4.8 s
- ○ 4.5 s
- ○ 3.8 s

**Explanation:**

For uniform circular motion, the centripetal force required to keep an object moving in a circle is provided by the tension in the string. The centripetal force \( F_c \) is given by the formula:

\[ F_c = \frac{m v^2}{r} \]

Where:
- \( m \) is the mass of the object (23 kg)
- \( v \) is the tangential velocity
- \( r \) is the radius of the circle (1.3 m)

Here, \( F_c = 51 \, \text{N} \). You can solve for \( v \) and then use it to find the period \( T \) of the revolution:

\[ v = \sqrt{\frac{F_c \cdot r}{m}} \]

The period \( T \) is the time it takes to make one complete revolution and is given by:

\[ T = \frac{2 \pi r}{v} \]

Use these formulas to calculate how long it takes for the mass to make one complete revolution.

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