A 4.00-kg object undergoes an acceleration given by a = (8.00 î + 4.0o j) m/s. (a) Find the resultant force acting on the object.

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### Physics Problem: Calculating Resultant Force and its Magnitude

A **4.00-kg** object undergoes an acceleration given by **\[ \mathbf{a} = (8.00 \mathbf{\hat{i}} + 4.00 \mathbf{\hat{j}}) \, \text{m/s}^2 \]**.

#### (a) Finding the Resultant Force Acting on the Object
Using Newton's second law, the resultant force **\[ \mathbf{F} \]** can be calculated using:
\[ \mathbf{F} = m \mathbf{a} \]
Where **\[ m \]** is the mass of the object and **\[ \mathbf{a} \]** is the acceleration.

\[ \Sigma \mathbf{F} = ( \_\_\_\_ \, \mathbf{\hat{i}} + \_\_\_\_ \, \mathbf{\hat{j}} ) \, \text{N} \]

#### (b) Finding the Magnitude of the Resultant Force
The magnitude of the resultant force can be obtained using the Pythagorean theorem:
\[ |\mathbf{F}| = \sqrt{(\Sigma F_x)^2 + (\Sigma F_y)^2} \]

\[ |\mathbf{F}| = \_\_\_\_ \, \text{N} \]

### Instructions
1. **Resultant Force in Component Form:** Calculate the x-component and y-component of the force using the given mass and acceleration components, then fill in the blanks.
   
2. **Magnitude of the Resultant Force:** Compute the resultant force's magnitude using the calculated components.

### Solution Steps
1. Calculate the force components:
   - \( F_x = m \times a_x \)
   - \( F_y = m \times a_y \)
   Here, \( a_x = 8.00 \, \text{m/s}^2 \) and \( a_y = 4.00 \, \text{m/s}^2 \).
2. Determine \( F_x \) and \( F_y \):
   - \( F_x = 4.00 \, \text{kg} \times 8.00 \, \text{m/s}^2 \)
   - \( F_y = 4.00 \, \text{kg} \times 4.00 \, \text{m/s
Transcribed Image Text:### Physics Problem: Calculating Resultant Force and its Magnitude A **4.00-kg** object undergoes an acceleration given by **\[ \mathbf{a} = (8.00 \mathbf{\hat{i}} + 4.00 \mathbf{\hat{j}}) \, \text{m/s}^2 \]**. #### (a) Finding the Resultant Force Acting on the Object Using Newton's second law, the resultant force **\[ \mathbf{F} \]** can be calculated using: \[ \mathbf{F} = m \mathbf{a} \] Where **\[ m \]** is the mass of the object and **\[ \mathbf{a} \]** is the acceleration. \[ \Sigma \mathbf{F} = ( \_\_\_\_ \, \mathbf{\hat{i}} + \_\_\_\_ \, \mathbf{\hat{j}} ) \, \text{N} \] #### (b) Finding the Magnitude of the Resultant Force The magnitude of the resultant force can be obtained using the Pythagorean theorem: \[ |\mathbf{F}| = \sqrt{(\Sigma F_x)^2 + (\Sigma F_y)^2} \] \[ |\mathbf{F}| = \_\_\_\_ \, \text{N} \] ### Instructions 1. **Resultant Force in Component Form:** Calculate the x-component and y-component of the force using the given mass and acceleration components, then fill in the blanks. 2. **Magnitude of the Resultant Force:** Compute the resultant force's magnitude using the calculated components. ### Solution Steps 1. Calculate the force components: - \( F_x = m \times a_x \) - \( F_y = m \times a_y \) Here, \( a_x = 8.00 \, \text{m/s}^2 \) and \( a_y = 4.00 \, \text{m/s}^2 \). 2. Determine \( F_x \) and \( F_y \): - \( F_x = 4.00 \, \text{kg} \times 8.00 \, \text{m/s}^2 \) - \( F_y = 4.00 \, \text{kg} \times 4.00 \, \text{m/s
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