Three forces acting on an object are given by F₁ = (−2.15î + 7.45ĵ) N, F₂ = (5.15î – 1.9ĵ) N, and F3 = (−40.5î) N. The object experiences an acceleration of magnitude 3.50 m/s². (a) What is the direction of the acceleration? ° (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 17.0 s? m/s (d) what are the velocity components of the object after 17.0 s? (Let the velocity be denoted by V.) v= Î + Ĵ) m/s

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Chapter1: Units, Trigonometry. And Vectors
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Three forces acting on an object are given by F₁ = (-2.15î + 7.45ĵ) N, F₂ = (5.15Î – 1.9ĵ) N, and ₹3 = (–40.51) N. The object experiences
an acceleration of magnitude 3.50 m/s².
1
(a) What is the direction of the acceleration?
° (counterclockwise from the +x-axis)
(b) What is the mass of the object?
kg
(c) If the object is initially at rest, what is its speed after 17.0 s?
m/s
(d) What are the velocity components of the object after 17.0 s? (Let the velocity be denoted by V.)
Î +
₁) m/s
V =
Transcribed Image Text:Three forces acting on an object are given by F₁ = (-2.15î + 7.45ĵ) N, F₂ = (5.15Î – 1.9ĵ) N, and ₹3 = (–40.51) N. The object experiences an acceleration of magnitude 3.50 m/s². 1 (a) What is the direction of the acceleration? ° (counterclockwise from the +x-axis) (b) What is the mass of the object? kg (c) If the object is initially at rest, what is its speed after 17.0 s? m/s (d) What are the velocity components of the object after 17.0 s? (Let the velocity be denoted by V.) Î + ₁) m/s V =
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