a = 3ti + 4tj , where The acceleration of a particle moving only on a horizontal xy plane is given by is in meters per second-squared and t is in seconds. At t = 0, the position vector 7 = (22.0m)7 + (45.0m)j locates the paticle, which then has the velocity vector v = (4.20m/s)/ + (1.70m/s)} . At t = 5.80 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis? (a) Number To.54 0.84 Units (b) NumberT52.31 Units ° (degrees)

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à = 3tî + 4tj , where
The acceleration of a particle moving only on a horizontal xy plane is given by
is in meters per second-squared and t is in seconds. At t = 0, the position vector
= (22.0m)/ + (45.0m)/ locates the paticle, which then has the velocity vector
(4.20m/s)/ + (1.70m/s)/. At t = 5.80 s, what are (a) its position vector in unit-vector
notation and (b) the angle between its direction of travel and the positive direction of the x axis?
(a) Number
0.54
+'
0.84
Units
(b) Number
Units
(degrees)
52.31
Transcribed Image Text:à = 3tî + 4tj , where The acceleration of a particle moving only on a horizontal xy plane is given by is in meters per second-squared and t is in seconds. At t = 0, the position vector = (22.0m)/ + (45.0m)/ locates the paticle, which then has the velocity vector (4.20m/s)/ + (1.70m/s)/. At t = 5.80 s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis? (a) Number 0.54 +' 0.84 Units (b) Number Units (degrees) 52.31
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