A 3kg block starts from rest at the top of 30o incline and slides with a = 1.78 m/s2. Find (a) the coefficient of kinetic friction between the block and the plane (b) the friction force acting on the block mg sin ehe mg cos 0 mg

A 3kg block starts from rest at the top of 30o incline and slides with a = 1.78 m/s2. Find (a) the coefficient of kinetic friction between the block and the plane (b) the friction force acting on the block mg sin ehe mg cos 0 mg

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Cart A has a mass of 10 kg. The slope has an incline of 20º. Rolling frictionis negligible. What is the mass of the hanging mass B if the cart is rolling upthe slope at constant velocity?
A block of mass 1.96kg is accelerated across a rough surface by a rope passing over a pulley, as shown in the figure below. The tension in the rope is 14.0N, and the pulley is 10.8cm above the top of the block. The coefficient of kinetic friction is 0.350. Calculate the value of x at which the acceleration becomes zero.
A daredevil bicyclıst moves at 7.0m/s in a horizontal cirde in a cylindrical "weli of dea th" of radius 4.0 m. (A.) Draw the free - bady diagram (B) What is the minimum coefficient of friction required ? man riding a bike
Write Newton's laws for a static system (1) EF, = mg sin 0 – µ̟n = 0 in component form. The gravity force has two components. (2) EF, = n - mg cos 0 = 0 Rearrange Equation (2) to get an n = mg cos e expression for the normal force n. Substitute the expression for n into EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ, Equation (1) and solve for tan 0. Apply the inverse tangent function to tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3° get the answer. LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. smaller component of gravitational force along the ramp…
A 375-lb block rests on a rough plane inclined 35o with the horizontal. If thecoefficients of friction between the block and the plane are 0.58 for static and 0.3 for kinetic respectively, determine whether or not the block is at rest.
You want to run up a hill starting from standstill. The hill is at an angle of 30 degrees with respect to hortizontal and has a coefficient of static friction of 0.3. How long will it take to reach a top speed of 25.2km/h?
Asap
1 kg is found A block of mass m = on an inclined plane that makes an angle 30° with the horizontal. The coefficient of static friction and coef- ficient of kinetic friction between the block and the incline are: µs and uk = 0.5. Take the positive di- rection to be up the inclined plane 0.6 %3D 130° With the block initially at rest, the acceleration of the block is
Two boxes (Box A = 9.7 kg and Box B = 5.4 kg) are connected by acord running over a pulley. The coefficient of kinetic friction betweenbox A and the table is 0.18. We ignore the mass of the cord and pulleyand any friction in the pulley, which means we can assume that a forceapplied to one end of the cord will have the same magnitude at theother end. We wish to find the tension of the cord while accelerating (inN), assuming the cord doesn’t stretch. As box B moves down, box Amoves to the right. Hint: Solve for the acceleration of the system first.
plz answer and do explain shortly.Thanks
Our 10.0-kg mystery box rests on a horizontal floor. The coefficient of static friction is 0.40 and the coefficient of kinetic friction is 0.30. Determine the force of friction, acting on the box if a horizontal applied force is exerted on it of magnitude: (a) 0, (b) 10 N, (c) 20 N Use 9.81m/s sqaured for the gravity and also F sub A unit for the applied force
A 50.0kg object is pushed across a level surface with a diagonal force of 550 N causing it to move forward at a constant velocity of 6.00 m/s. Calculate the coefficient of kinetic friction